A 9.5 kg object undergoes an acceleration of 3.3m/s^2. What is the magnitude of the next external force acting on it
1 answer:
The net external force is 31.4 N
Explanation:
We can solve this problem by applying Newton's second law, which states that the net force acting on an object is equal to the product between its mass and its acceleration:
where
F is the net force
m is the mass
a is the acceleration
For the object in this problem, we have:
m = 9.5 kg is the mass
is the acceleration
Solving for F, we find the net force:
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Answer:
- Bigger mass of planet B
- orbiting closer to planet B
Explanation:
The orbital velocity of the vessel around the planet can be found by equalizing the force of gravity between the vessel and the planet and the centripetal force:
where
G is the gravitational constant
m is the mass of the vessel
M is the mass of the planet
r is the distance between the vessel and the centre of the planet
v is the orbital velocity of the vessel
Re-arranging the formula, we find an expression for v:
We see that:
- the bigger the mass of the planet, M, the bigger the velocity
- the bigger the distance between the vessel and the planet, r, the smaller the velocity
So, the correct choices that increase the orbital velocity are:
- Bigger mass of planet B
- orbiting closer to planet B