A 9.5 kg object undergoes an acceleration of 3.3m/s^2. What is the magnitude of the next external force acting on it
1 answer:
The net external force is 31.4 N
Explanation:
We can solve this problem by applying Newton's second law, which states that the net force acting on an object is equal to the product between its mass and its acceleration:
where
F is the net force
m is the mass
a is the acceleration
For the object in this problem, we have:
m = 9.5 kg is the mass
is the acceleration
Solving for F, we find the net force:
Learn more about Newton's second law:
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Missing graph. I attach it in the answer.
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where a is the acceleration and t is the time.
Given the previous equation, if we plot v(t) versus t, we find a straight line; moreover, a (the acceleration) represents the slope of the curve.
Looking at the graph, we see that when the time goes from 10 s to 20 s, the velocity increases from 4 m/s to 6 m/s. Therefore the slope of the curve is
and this corresponds to the acceleration.
So, the correct answer is <span>0.2 m/s2.</span>
In a uniformly accelerated motion, the velocity at time t is given by:
where a is the acceleration and t is the time.
Given the previous equation, if we plot v(t) versus t, we find a straight line; moreover, a (the acceleration) represents the slope of the curve.
Looking at the graph, we see that when the time goes from 10 s to 20 s, the velocity increases from 4 m/s to 6 m/s. Therefore the slope of the curve is
and this corresponds to the acceleration.
So, the correct answer is <span>0.2 m/s2.</span>