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just olya [345]
2 years ago
12

Where is UTC the local time?

Physics
1 answer:
Dmitrij [34]2 years ago
5 0

UTC is generally adopted as the local time at Prime Meridian (PM).

<h3>What is UTC?</h3>

UTC is an abbreviation for Coordinated Universal Time and it can be defined as a local time standard by which all clocks, time and time zones are regulated around the world.

This ultimately implies that, Coordinated Universal Time (UTC) is generally adopted as the local time at Prime Meridian (PM) because it nominally reflects mean solar time.

Read more on UTC here: brainly.com/question/14333785

#SPJ12

You might be interested in
If the range of a projectile's trajectory is six times larger than the height of the trajectory, then what was the angle of laun
zvonat [6]

Answer:

H = 1/2 g t^2    where t is time to fall a height H

H = 1/8 g T^2   where T is total time in air  (2 t  = T)

R = V T cos θ       horizontal range

3/4 g T^2 = V T cos θ       6 H = R    given in problem

cos θ = 3 g T / (4 V)           (I)

Now t = V sin θ / g     time for projectile to fall from max height

T = 2 V sin θ / g

T / V = 2 sin θ / g

cos θ = 3 g / 4 (T / V)     from (I)

cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ

tan θ = 2/3      

θ = 33.7 deg

As a check- let V = 100 m/s

Vx = 100 cos 33.7 = 83,2

Vy = 100 sin 33,7 = 55.5

T = 2 * 55.5 / 9.8 = 11.3 sec

H = 1/2 * 9.8 * (11.3 / 2)^2 = 156

R = 83.2 * 11.3 = 932

R / H = 932 / 156 = 5.97        6 within rounding

3 0
3 years ago
Your best friend weighs 81.5 kg and is a rugby player. In one of his games, he slides to a stop in a phenomenal manner. The coef
Alex777 [14]

A. The acceleration during the slide is 6.86 m/s²

B. The time taken to slide until he stops is 1.2 s

<h3>How to determine the force of friction</h3>
  • Mass (m) = 81.5 Kg
  • Coefficient of friction (μ) = 0.7
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 N
  • Frictional force (F) =?

F = μN

F = 0.7 × 798.7

F = 559.09 N

<h3>A. How to determine the acceleration</h3>
  • Mass (m) = 81.5 Kg
  • Frictional force (F) = 559.09 N
  • Acceleration (a) =?

a = F / m

a = 559.09 / 81.5

a = 6.86 m/s²

<h3>B. How to determine the time </h3>
  • Initial velocity (u) = 8.23 m/s
  • Final velocity (v) = 0 m/s
  • Decceleration (a) = -6.86 m/s²
  • Time (t) =?

a = (v – u) / t

t = (v – u) / a

t = (0 – 8.23) / -6.86

t = 1.2 s

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

4 0
2 years ago
Three resistors are connected in series to a 42.1 V battery: R1 = 2.96 Ω, R2 = 7.48 Ω and R3 = 7.42 Ω. Now, as R3 heats up, its
LuckyWell [14K]

Answer:

dP/dt = 26.12 W/s

Explanation:

First, we need to find the value of dt at the instant when R₃ becomes 91.7 Ω. Therefore, we use:

dR₃/dt = 0.552 Ω/s

where,

dR₃ = Change in value of resistance 3 = 91.7 Ω - 7.42 Ω = 84.28 Ω

dt = time interval = ?

Therefore,

84.28 Ω = (0.552 Ω/s)(dt)

dt = (84.28 Ω)/(0.552 Ω/s)

dt = 152.68 s

Now, we find change in power (dP):

dP = V(R₁ + R₂ + dR₃)

dP = (42.1 V)(2.96 Ω + 7.48 Ω + 84.28 Ω)

dP = 3987.71 W

Dividing by dt:

dP/dt = 3987.71 W/152.68 s

<u>dP/dt = 26.12 W/s</u>

7 0
3 years ago
1. Do you think your memories can be altered? Explain
PilotLPTM [1.2K]

Answer:

Yes

Explanation:

I think our memories can be altered by emotions. If someone tells you something over and over and over again with strong emotion you will start to remember that more than the memory.

Emotions are very powerful and if you feel a certain emotion connected with a different memory I think that is stronger and can trick your brain into thinking that is the memory because of the strong emotion, even though the true memory was right, since it might not have as strong of mental emotion your brain will think that is the false memory because whatever is more memorable your brain will remember.

If that makes any sense,

3 0
3 years ago
What is the speed of sound at the atmospheric temperature of 30°c?
OlgaM077 [116]
We know the equation for calculation of speed of sound at temperature:
<span>v = 331 m/s + (0.6 m/s/C) * T
</span>Here, T = 30 C
v = 331 m/s + (0.6 m/s/C) * 30 C
v = 331 m/s + 18 m/s
v = 349 m/s

In short, Your Answer would be 349 m/s

Hope this helps!
6 0
4 years ago
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