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2 years ago

Where is UTC the local time?

Physics

1 answer:

Dmitrij [34]2 years ago

5 0

UTC is generally adopted as the local time at Prime Meridian (PM).

UTC is an abbreviation for Coordinated Universal Time and it can be defined as a local time standard by which all clocks, time and time zones are regulated around the world.

This ultimately implies that, Coordinated Universal Time (UTC) is generally adopted as the local time at Prime Meridian (PM) because it nominally reflects mean solar time.

Read more on UTC here: brainly.com/question/14333785

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Can someone help me with this please

andrezito [222]

Carbon: C, 12.011, 6, 12
Oxygen: O, 8, 8, 8, 16
Boron: B, 10.811, 5, 5, 11

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3 years ago

Two satellites revolve around the Earth. Satellite A has mass m and has an orbit of radius r. Satellite B has mass 6m and an orb

melomori [17]

Answer:

aaaaa

Explanation:

M = Mass of the Earth

m = Mass of satellite

r = Radius of satellite

G = Gravitational constant

$F=G\frac{Mm}{r^2}$

$F=G\frac{M6m}{r_b^2}$

$G\frac{Mm}{r^2}=G\frac{M6m}{r_b^2}\\\Rightarrow \frac{1}{r^2}=\frac{6}{r_b^2}\\\Rightarrow \frac{r_b^2}{r^2}=6\\\Rightarrow \frac{r_b}{r}=\sqrt{6}\\\Rightarrow r_b=2.44948r$

$r_b=2.44948r$

8 0

4 years ago

A 140 g air-track glider is attached to a spring. The glider is pushed in 8.2 cm against the spring, then released. A student wi

max2010maxim [7]

Answer:

Explanation:

The period of oscillation is given as

T=2π√m/k

Making k subject of the formula

Square both sides of the equation

T²=4π²(m/k)

Cross multiply

T²k=4π²m

Then, divide through by T²

k=4π²m/T²

Where

k is spring constant

m is the mass of the bob

And T is the period of the oscillation

m=140g=0.14kg

14 oscillations takes 14 seconds

Then the period is

T=time/oscillation

T=14/14

T=1sec

Then,

k=4π²m/T²

k=4π²×0.14/1²

k=1.76N/m

Then, the spring constant is 1.76N/m

4 0

4 years ago

A train departs from its station at a constant acceleration of 5m/s2. What is the speed of the train at the end of 20 seconds

Shalnov [3]

a = v/t

v = a.t

v = 5 * 20 = 100m/s

8 0

4 years ago

The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.0 cm apart with a 20 kV potential

Julli [10]

Answer:

A) electric field strength between the plates;E = 2 x 10^(6) N/C

B) exit velocity;v = 8.39 x 10^(7) m/s

Explanation:

We are given;

Potential difference; V = 20 kV = 20000 V

Distance between the 2 parallel plates; d = 1cm = 0.01 m

A) The electric field strength will be gotten from;

E = V/d

E = 20000/0.01

E = 2000000

E = 2 x 10^(6) N/C

B) For exit speed, we'll use the formula for Kinetic energy; KE = (1/2)mv²

KE is also expressed as; V•q_e

Thus,

(1/2)mv² = V•q_e

Where;

V is potential difference = 20000 V

Q_e is charge of electron which has a constant value of; (1.6 x 10^(-19))C

m is mass of electron with a constant value of (9.1 x 10^(-31)) kg

v is the velocity

Thus, making v the subject, we have;

v = √((2V•q_e)/m)

v = √((2 x 20000•(1.6 x 10^(-19)))/(9.1 x 10^(-31)))

v = 83862786 m/s or

v = 8.39 x 10^(7) m/s

3 0

3 years ago