Answer:
5702.88 J or 5.7mJ
Explanation:
Given that :
C 1 = 6.0-μF
C 2 = 4.0-μF
V 1 = 50V
V 2 = 34V
Note that : Q = CV
Q 1 = C1 * V1
Q 1 = 50×6 = 300μC
Q 2 = 34×4 = 136μC
Parallel connection = C 1 + C 2
= 6+4 = 10μC
V = Qt/C
Where Qt = Q1+Q2
V = Q1+Q2/C
V = 300+136/10
V = 437/10
V = 43.6volts
Uc1 = 1/2×C1V^2
= 1/2 × 6μF × 43.6^2
= 1/2 × 6μF × 1900.96
= 3μF × 1900.96volts
= 5702.88J
= 5702.88J/1000
= 5.7mJ
In this question, we know that mass= 10 kg = 10 x 1000 = 10,000 g
Distance = 1 m and Time = 0.5 s
Power = Force x Velocity
Velocity = Distance / Time = 1 m / 0.5 s = 2 m/s
So, Power = Force x (Distance / Time)
But Force= Mass x Acceleration due to gravity (g)
So, Force = 10 kg x 9.8 m/s

= 98
Therefore, Power =Force x Velocity= 98 x 2 =
196 W
The direction of torque τ this method is mathematically given as
D=X
Option A is correct.
<h3>What is the
direction of
torque?</h3>
Generally, the equation for torque is mathematically given as
τ = r X F
Hence to decipher the torque direction with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r
- We utilize our right hand.
- Place our right-hand fingers along the path of r
- Place our right-hand palm on F
- Then slowly we sweep r into F.
- The path or direction of the thumb will provide the direction of the torque.
In conclusion, the direction of this method is
D=X Option A.
Read more about torque
brainly.com/question/6855614
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Answer:
the acceleration 
Explanation:
Given that:
the initial speed v₁ = 0 m/s i.e starting from rest ; since the car accelerates at a distance Δx = 6 miles in order to teach that final speed v₂ of 63.15 km/h.
So; the acceleration for the first 6 miles can be calculated by using the formula:
v₂² = v₁² + 2a (Δx)
Making acceleration a the subject of the formula in the above expression ; we have:
v₂² - v₁² = 2a (Δx)




Thus;
Assume the car moves in the +x direction;
the acceleration 