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sineoko [7]
3 years ago
7

Find the midpoint of the segment between the points (8,−10) and (−10,−8) A. (−1,−9) B. (0,−6) C. (0,0) D. (−1,2)

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

Hey there!

We can use the midpoint formula to find that the midpoint is (-1, -9).

Let me know if this helps :)

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Complete the equivalent ratio = 9/4 = 81/?
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Answer:

81/36

Step-by-step explanation:

81/9 is 9

9 times 4 is 36

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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 71°, a = 27, c = 26
guajiro [1.7K]

We have

SinC/ c  = Sin A / a

Sin 71/ 26 = Sin A / 27

Sin A  = 27 Sin 71 /  26  = about .982

So°

Sin-1(.982)  = A  = 79. 08°

Then angle B = 180 - 71 - 79.08 = 29.92°

And b is given by

b/sin29.92  = 26/sin 71

b = 26sin29.92/sin71 =  about 13.72

But A could also be an obtuse angle = 180 - 79.08 =  100.92°

So we have

B = 180 - 71 - 100.92 = 8.08°

And we have

b / sin 8.08  = 26/sin71

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8 0
3 years ago
Identify the triangle PQR as isosceles​ (two sides of equal​ length), equilateral​ (three sides of equal​ length), or a scalene
Ipatiy [6.2K]

Answer:

Isosceles

Step-by-step explanation:

In order to figure what type of triangle this is out, we need to start by plotting the given points. That will help us visualize the triangle better and see if our conclusions make sense. (See attached picture).

Once we got the triangle, the strategy to follow is to use the distance between two points formula to see what the measurement of each side of the triangle is. This will help us determine if 2, 3 or none of the sides of the tirangle are the same.

The distance formula is the following:

distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

so now we can find the desired distances, let's start with the distance between P and Q:

|PQ|=\sqrt{(-4-0)^{2}+(9-8)^{2}}

which yields:

|PQ|=\sqrt{17}

next, let's find the distance between P and R:

|PR|=\sqrt{(-4-(-3))^{2}+(9-5)^{2}}

which yields:

|PR|=\sqrt{17}

and finally the distance between Q and R:

|QR|=\sqrt{(0-(-3))^{2}+(8-5)^{2}}

which yields:

|QR|=3\sqrt{2}

As you  may see from the result, only two of the three sides are the same, |PQ| and |PR|, so this will be an Isosceles triangle.

6 0
3 years ago
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