2 years ago

Find the product of (4z2 + 7z – 8) and (–z + 3).

Mathematics

2 answers:

loris [4]2 years ago

6 0

Answer:

(4z2+7z−8)(−z+3)

=(4z2+7z+−8)(−z+3)

=(4z2)(−z)+(4z2)(3)+(7z)(−z)+(7z)(3)+(−8)(−z)+(−8)(3)

=−4z3+12z2−7z2+21z+8z−24

=−4z^3+5z^2+29z−24

babymother [125]2 years ago

3 0

Answer:

3, 8

Step-by-step explanation:

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Read 2 more answers

Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4). What is the y-coordinate of the midpoint of line segment YZ?

tatiyna

Given:

Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4).

To find:

The y-coordinate of the midpoint of line segment YZ.

Solution:

Midpoint formula:

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

The endpoints of the line segment YZ are Y(-3,-6) and Z(7,4). So, the midpoint of YZ is:

$Midpoint=\left(\dfrac{-3+7}{2},\dfrac{-6+4}{2}\right)$

$Midpoint=\left(\dfrac{4}{2},\dfrac{-2}{2}\right)$

$Midpoint=\left(2,-1\right)$

Therefore, the y-coordinate of the midpoint of line segment YZ is -1.

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