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love history [14]
3 years ago
7

Find the product of (4z2 + 7z – 8) and (–z + 3).

Mathematics
2 answers:
loris [4]3 years ago
6 0

Answer:

(4z2+7z−8)(−z+3)

=(4z2+7z+−8)(−z+3)

=(4z2)(−z)+(4z2)(3)+(7z)(−z)+(7z)(3)+(−8)(−z)+(−8)(3)

=−4z3+12z2−7z2+21z+8z−24

=−4z^3+5z^2+29z−24

babymother [125]3 years ago
3 0

Answer:

3, 8

Step-by-step explanation:

DANCE ON A D>?I>?C>?K LIKE YOUVE BEEN SERVED I LIKE IT WITH A LITTLE BIT OF CURVE HIT THIS .p..u...ss...y WITH AN UPPERCUT CALL IT CALL IT CAPTIAN HOOK

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Answer:

The answer is c because of how the equation is set and made

5 0
1 year ago
A line passes through the point (4,7) and has a slope of -5/2.
pshichka [43]

Answer:

y=-\frac{5}{2} x+17

Step-by-step explanation:

3 0
2 years ago
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2 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±3) and foci at (0, ±7)
Nitella [24]

The equation of a hyperbola is:

(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1

 

So what we have to do is to look for the values of the variables:

<span>For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9</span>

<span>
c = 7 (distance from center to vertices; given from the foci)
c^2 = 49</span>

 

<span>By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2 </span>

<span>b^2 =  49 – 9</span>

<span>b^2  = 40

</span>

Therefore the equation of the hyperbola is:

<span>(x^2 / 9) – (y^2 / 40) = 1</span>

5 0
3 years ago
Read 2 more answers
Pick the correct answer <br> Please help thanks :)
meriva

Answer:

B

Step-by-step explanation:

First create the equation that has slope of -1 in the form of y=mx+b. Because the slope is -1, m=-1, so the equation is y=-x+b. Now we see that we are given the point (-3, 8) as an intersection point. Substitute x and y for -3 and 8 in our equation. With this information, our equation becomes 8=3+b. Solving, b=5. Our equation is now y=-x+5.

Simplifying all of the answer choices, we have

A. y=-x-5

B. y=-x+5

C. y=-x-5

D. and E. as what they already show

The only answer that matches is B.

5 0
1 year ago
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