The temperature would be 30C if the water is at the same temp as the lab <span />
Δ, namely δ− or δ+. Partial charges<span>are created due to the asymmetric distribution of electrons in chemical bonds. For example, in a </span>polar covalent<span> bond like HCl, the shared electron oscillates between the bonded atoms.</span>
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Answer: 633.6 g of
can be produced from the decomposition of 4.8 moles of 
Explanation:
The balanced chemical equation for decomposition of
is :
According to stoichiometry :
1 mole of
produce = 3 moles of 
Thus 4.8 moles of
will rproduce=
of 
Mass of 
Thus 633.6 g of
can be produced from the decomposition of 4.8 moles of 
<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399
<u>Explanation:</u>
Mass defect is defined as the difference in the mass of an isotope and its mass number.
The equation used to calculate mass defect follows:
![\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M](https://tex.z-dn.net/?f=%5CDelta%20m%3D%5B%28n_p%5Ctimes%20m_p%29%2B%28n_n%5Ctimes%20m_n%29%5D-M)
where,
= number of protons
= mass of one proton
= number of neutrons
= mass of one neutron
M = mass number of element
We are given:
An isotope of phosphorus which is 
Number of protons = atomic number = 15
Number of neutrons = Mass number - atomic number = 31 - 15 = 16
Mass of proton = 1.00728 amu
Mass of neutron = 1.00866 amu
Mass number of phosphorus = 30.973765 amu
Putting values in above equation, we get:
![\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399](https://tex.z-dn.net/?f=%5CDelta%20m%3D%5B%2815%5Ctimes%201.00728%29%2B%2816%5Ctimes%201.00866%29%5D-30.973765%5C%5C%5C%5C%5CDelta%20m%3D0.27399)
Hence, the mass defect for the formation of phosphorus-31 is 0.27399