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Genrish500 [490]
3 years ago
12

5 cakes cost £4 how much do 7 cakes cost

Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

£5.60

divide £4 by 5 to obtain the cost of 1 cake then multiply this value by 7 for the cost of 7 cakes

5 → £4

7 → £4 × \frac{7}{5} = £5.60


Nostrana [21]3 years ago
4 0

You can solve this using proportion.

5 = 4

7 = ?

7(4)/5= 5.6

7 cakes cost £5.6

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Answer:

1) S=\{1,2,3,4,5,6\}

2) O=\{1,3,5\}

Step-by-step explanation:

Given : A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.

To find : Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of rolling an odd number. If there is more than one element in the set, separate them with commas ?

Solution :

A number cube with faces labeled from 1 to 6 will be rolled once.

The sample space describing all possible outcomes is given by

S=\{1,2,3,4,5,6\}

All of the outcomes for the event of rolling an odd number is given by

O=\{1,3,5\}

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3 years ago
Suppose we have a population whose proportion of items with the desired attribute is p = 0:5. (a) If a sample of size 200 is tak
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Answer:

a. If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b. If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

Step-by-step explanation:

This problem should be solved with a binomial distribution sample, but as the size of the sample is large, it can be approximated to a normal distribution.

The parameters for the normal distribution will be

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/200}= 0.0353

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.0353}=-0.85\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.0353}=0.28

We can now calculate the probabilities:

P(0.47

If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b) If the sample size change, the standard deviation of the normal distribution changes:

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/100}= 0.05

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.05}=-0.6\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.05}=0.2

We can now calculate the probabilities:

P(0.47

If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

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Answer:

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Step-by-step explanation:

<u>Proportional relationship equation:</u>

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<u>Use the given point to work out the value of k:</u>

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<u>In our case the equation is:</u>

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Answer:

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Step-by-step explanation:

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