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3 years ago

What is the area of the trapezoid shown below?

Mathematics

2 answers:

tatyana61 [14]3 years ago

7 0

Answer:

48 i hope this helps! :)

Step-by-step explanation:

12 * 4 = 48

5 * 4 = 20

12 - 5 = 7

7 * 4 = 28

28 + 20 = 48

Gnom [1K]3 years ago

6 0

Answer:

34 in²

Step-by-step explanation:

Use the formula A = (a + b)(h/2)

Then plug in the numbers

A = (12+5)(4/2)

A = 17(2)

A = 34

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Which equation shows a correct strategy and product for the expression shown? 0.6x0.9

12345 [234]

Answer:

.19

Step-by-step explanation:

3 0

2 years ago

Witch one is this the answer for I have a lot more questions so stick around if you can help me

tatiyna

-70.04 B would be the correct one

4 0

3 years ago

Please help me<br> This is analytic geometry

Vlada [557]

Answer:

The coordinates of point B are (-3,-3).

Step-by-step explanation:

Let $A(x,y) = (6,-6)$ , $C(x,y) = (-6,-2)$ and $\overrightarrow{AB} = \frac{3}{4}\cdot \overrightarrow{AC}$ , then we have the following formula by vectorial definition of a line segment:

$\overrightarrow{AB} = \frac{3}{4}\cdot \overrightarrow{AC}$

$B(x,y) -A(x,y) = \frac{3}{4}\cdot [C(x,y)-A(x,y)]$

$B(x,y) = \frac{3}{4}\cdot C(x,y) +\frac{1}{4}\cdot A(x,y)$

$B(x,y) = \frac{3}{4}\cdot (-6,-2)+\frac{1}{4}\cdot (6,-6)$

$B(x,y) = (-3, -3)$

5 0

3 years ago

Solve quadratic formulax^2-4x+3=0

bekas [8.4K]

The general formula for a equation of the form:

$ax^2+bx+c=0$

is:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

$\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}$

then:

$x_1=\frac{4+2}{2}=\frac{6}{2}=3$

and

$x_2=\frac{4-2}{2}=\frac{2}{2}=1$

Therefore, x=3 or x=1.

8 0

11 months ago

Show away to count from 668to900 using ones,ten,and hundred

sweet [91]

Not sure what you mean, exactly, but Ill try.

668, using 2 ones, go to 670. Using 3 tens, go to 700. Using 2 hundreds get to 900. Hope this helped :)

5 0

3 years ago