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Flauer [41]
2 years ago
9

A carpenter used 1/3 able to finish of a box of nails while working on a birdhouse and was able to finish 1/5 of it. At this rat

e, how many boxes will he need to finish the entire birdhouse?​
Mathematics
1 answer:
aleksandrvk [35]2 years ago
7 0

Answer:

He will need 1 and 2/3 boxes

Step-by-step explanation:

1/5= 1/3 boxes

5/5= 1/3* 5 boxes

Hope this helps!

Let me know if it does

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Which graph represents the function -2x - 5y = -10? <br> Please explain!!
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The answer would be J because if the equation was transferred into a positive then it would be 2y and 5x marking 5x on the bottom and 2y vertically.
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If you separate the triangles, you'll notice that both are literally the same triangle because all angles are the same.
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Rename 5/6 and 14/15 using the least common denominator.
baherus [9]

Answer:

\frac{25}{30}~and~\frac{28}{30}

  • Multiply 5 by 5 to get your first parameter.

5 * 5 = 25

  • Multiply 6 by 5 to get the denominator, or your second parameter.

5 * 6 = 30

  • For the second fraction, \frac{14}{15}, you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.

14 * 2 = 28

  • Now, multiply 15 by 2

15 * 2 = 30

  • The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.

25~and~30 -- > \frac{25}{30}

28~and~30-- > \frac{28}{30}

________________________________________________________

Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

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<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

8 0
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Answer:

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Step-by-step explanation:

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This gives us

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Since the base of the exponential function and the logarithm is the same (x), they'll cancel out one another

This leaves us with

y= x^\frac{1}{2}

Hence, the exponential form of the expression

log_xy= \frac{1}{2} is y= x^\frac{1}{2}

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Answer:B

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