Answer:
SSS
∆PQR = 43
Step-by-step explanation:
The postulate to solve ∆PQR ≅ ∆STU is SSS. Both of the triangles have all three sides given, which means it can be solved for congruence.
9 + 6y + 5 + 14 = 9 + 8y +14
28 + 6y = 9 + 8y + 14
28 + 6y = 8y + 23
-6y -6y
--------------------------
28 = 2y + 23
-23 -23
---------------------
5 = 2y
---- ----
2 2
2.5 = y
9 + 14 + 6(2.5) + 5
23 + 15 + 5
23 + 20
43
∆PQR = 43
Answer:
13
Step-by-step explanation:
Answer:
(B)(negative 2) (4)
Step-by-step explanation:
The arrow on the number line ended at negative 8 (-8).
Given the options:
(A) (negative 3) (4) =(-3)(4)=-12
(B)(negative 2) (4) =(-2)(4)=-8
(C) (2)(4)=8
(D)(3)(4)=12
The expected product is -8 since that is where the arrow ended. Therefore, the product that is modeled by the number line is that which gives a result of -8. The correct option is B.
(B)(negative 2) (4) =(-2)(4)=-8
Well the first three is in this place value _ - _ _ where the dash is i that is hundred second one is tens
Answer:
<em>96π units²</em>
Step-by-step explanation:
Find the diagram attached
Area of a sector is expressed as;
Area of a sector = θ/2π * πr²
Given
θ = 3π/4
r = 16
Substitute into the formula
area of the sector = (3π/4)/2π * π(16)²
area of the sector = 3π/8π * 256π
area of the sector = 3/8 * 256π
area of the sector = 3 * 32π
<em>area of the sector =96π units²</em>
