All categories

3 years ago

Consider the two planes.

Mathematics

2 answers:

statuscvo [17]3 years ago

5 0

Answer:

Step-by-step explanation:

In the given figure, you can observe that plane R and plane Q are perpendicular. So, neither of lines inside the plane R can be parallel to line c, because it's placed in a perpendicular plane.

This means that they only line that can be parallel to line c, it's actually line d, because it's in the same plane, and the figure shows that they have the same direction, which allow us to deduct that they are parallel.

IceJOKER [234]3 years ago

3 0

Answer:

Line d

Step-by-step explanation:

Line A could not be parallel to line C and neither cold line B because they would cross at some point. Line D is parallel because it would not cross line C at any point. Plane Q oculd not be parallel to line C because it is a plane and it is perpendicular to line C.

You might be interested in

NEED HELP ASAP!!!!!!!!!!!

zhenek [66]

The equation $x=tan^{-1}(\frac{12}{5})$ can be used to find the measure of ∠BAC ⇒ 2nd answer

Step-by-step explanation:

Let us revise the trigonometry ratios in the right triangle ABC, where B is the right angle, AC is the hypotenuse, AB and BC are the legs of the triangle

The trigonometry ratios of the ∠BAC, the opposite side to this angle is BC and the adjacent side to it is AB are

$sin(BAC)=\frac{opposite}{hypotenuse}=\frac{BC}{AC}$
$cos(BAC)=\frac{adjacent}{hypotenuse}=\frac{AB}{AC}$
$tan(BAC)=\frac{opposite}{adjacent}=\frac{BC}{AB}$

In Δ ABC

∵ ∠ BCA is a right angle

∴ The hypotenuse is AB

∵ The adjacent side to ∠CAB is AC

∵ The opposite side to ∠CAB is BC

∵ AB = 13 units ⇒ hypotenuse

∵ CB = 12 units ⇒ opposite

∵ AC = 5 units ⇒ adjacent

- Let us find the trigonometry ratios of angle BAC

∵ m∠CAB is x

∵ $sin(x)=\frac{BC}{AB}$

∴ $sin(x)=\frac{12}{13}$

∴ $x=sin^{-1}(\frac{12}{13})$

∵ $cos(x)=\frac{AC}{AB}$

∴ $cos(x)=\frac{5}{13}$

∴ $x=cos^{-1}(\frac{5}{13})$

∵ $tan(x)=\frac{BC}{AC}$

∴ $tan(x)=\frac{12}{5}$

∴ $x=tan^{-1}(\frac{12}{5})$

The equation $x=tan^{-1}(\frac{12}{5})$ can be used to find the measure of ∠BAC

Learn more:

You can learn more about the trigonometry ratios in brainly.com/question/4924817

#LearnwithBrainly

4 0

3 years ago

Read 2 more answers

In this figure triangle BAE is congruent to triangle DEA. Which statement is true by CPCTC?

Vsevolod [243]

The correct answer is the last option

5 0

3 years ago

Read 2 more answers

Four streets enter a traffic circle at points A B C and D name six arcs formed by the streets.

lilavasa [31]

Arcs are just sections of the circle
so lets say you had a pizza

and you put some points on the crust, the legnth of the crust from point to point is that arc

example
if you put poins A and B, then arc AB is the crust between points A and B

arcs can include other points as well
and arc AB=arc BA

so
I wil name easy arcs first
arc AB
arc BC
arc CD
ard DA

now ones that include others
arc AC
arc BD

so the arcs you might want to list are

arc AB
arc BC
arc CD
ard DA
arc AC
arc DB

5 0

3 years ago

Explain how an estimate helps you place the decimal point when multiplying 3.7×5.1

Cloud [144]

If you estimated 3.7 to 4 and 5.1 to 5 the answer would be 20. You would have 20 and now you can think is 20 a reasonable answer for 3.7x5.1. The answer for 3.7x5.1=18.87, so the answer is yes.

Hope that helped:)

3 0

3 years ago

Read 2 more answers

A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)

stiks02 [169]

Answer: 82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB $=\sqrt{(9+1)^2+(-1-7)^2}$ units [By distance formula : $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ ]