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3 years ago

10

Which function has a vertex at the origin?

1 answer:

Zarrin [17]3 years ago

3 0

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
-x^2\implies -(x-\stackrel{h}{0})^2\stackrel{k}{+0}$

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Elina [12.6K]

<u>ANSWER</u>

It is not one-to-one function

<u>EXPLANATION</u>

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The graph described in the question looks like the one in the attachment.

A horizontal line drawn in red cuts the graph at more than one point.

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3 years ago

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

Use the surface area formula with the given numbers.

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3 years ago

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Virty [35]

Answer:

<u>Linear</u>

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Step-by-step explanation:

Linear equations have the highest degree to be 1.

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is also linear.

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3 years ago

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netineya [11]

Answer:

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b = 119 <-- subtracted 61 from both sides

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87 + 6x + 3 = 180 <-- take out parantheses

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3 years ago