Question

Which function has a vertex at the origin?

Answer 1

$\bf \qquad \textit{parabola vertex form}\\\\ \begin{array}{llll} y=a(x-{{ h}})^2+{{ k}}\\\\ x=a(y-{{ k}})^2+{{ h}} \end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -------------------------------\\\\ -x^2\implies -(x-\stackrel{h}{0})^2\stackrel{k}{+0}$