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3 years ago

10

Which function has a vertex at the origin?

1 answer:

Zarrin [17]3 years ago

3 0

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
-x^2\implies -(x-\stackrel{h}{0})^2\stackrel{k}{+0}$

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In the adjoining figure, the parallel lines are marked by arrow lines. The value of angle 1 is:

dlinn [17]

Answer:

20°

Step-by-step explanation:

40°, 70° and 90° are the measures of the three angles of the quadrilateral.

Measure of fourth angle of the Quadrilateral

= 360° - (40° + 70° + 90°)

= 360° - 200°

= 160°

Measure of angle 1 will be equal to the measure of the linear pair angle of 160° as they are corresponding angles.

Thus,

$m\angle 1 = 180\degree- 160\degree$

$\implies\huge\purple{\boxed{ m\angle 1 = 20\degree}}$

Alternate method:

$m\angle 1 = 180\degree- [360\degree-(40\degree+70\degree+90\degree)]$

$\implies m\angle 1 = 180\degree- [360\degree-200\degree]$

$\implies m\angle 1 = 180\degree- 160\degree$

$\implies m\angle 1 = 20\degree$

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Simora [160]

Answer:

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Making your equation simplified to

1/2 + 1/2

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Step-by-step explanation:

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lilavasa [31]

Answer:

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Step-by-step explanation:

Let

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using a graphing tool

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(6x–1)(6x+1) - 4x(9x+2) = −1

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djyliett [7]

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