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Serjik [45]
3 years ago
9

Please help with this question

Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:

10X + 20 +5X +25 = 180

15x=180-45

X= 135/15

X=9

Please mark me brainliest and thank me and rate me. Sis.

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Answer: b+95+34=180, b+129=180, 51

Step-by-step explanation:

b+95+34=180 works because the angles add to form a straight angle.

From this, we can obtain b+129=180 by adding the two constants.

Subtracting 129 from both sides, we get b=51.

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Ayyyy ayudaa <br> ~conversión de fracciones y decimales ~
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2 years ago
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Leslie has a rectangular patio. She measures it and finds out it is 2135 feet long by 1115 feet wide. She wants to know how many
larisa86 [58]

Answer: (1) Leslie will need 2,380,525 square tiles (1 foot by 1 foot each)

(2) She will have to spend $1,785,393.75 to cover her patio.

Step-by-step explanation: Please refer to the picture attached.

The rectangular patio has been designed and as shown in the diagram has on side measuring 2135 ft and the other side measuring 1115 ft. This means, in order to cover the entire patio, she would have to cover an entire area defined as 2,135 feet into 1,115 feet. If one tile measures 1 foot long by 1 foot wide, the total number of tiles to cover the patio can simply be derived as;

Area = L x W

Where the length is 2135 and the width is 1115,

Area = 2135 x 1115

Area = 2380525

**Having in mind that one tile measures 1 ft by 1 ft, the area of each tile is given as

Area = L x W

Area = 1 x 1

Area = 1 square foot**

(1) The above calculation shows that Leslie would be using up a total of 2,380,525 square tiles to completely cover her patio.

(2) Having been told that each square foot of tile costs 75 cents ($0.75), the total amount spent to cover her patio would be calculated as follows;

Cost = Area x cost per tile

Cost = 2380525 x 0.75

Cost = 1785393.75

The total cost therefore is $1,785,393.75

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3 years ago
Drag expressions to complete each equation.
Maru [420]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

a^{b} × a^{c} = a^{b+c}

\frac{a^{b} }{a^{c} } = a^{b-c}

a^{c} × b^{c} = (ab)^{c}

7 0
3 years ago
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