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Reika [66]
2 years ago
10

If each person takes up 2.25 square feet of space, how many people can fit into an area that is 15 feet by 30 feet?

Mathematics
1 answer:
3241004551 [841]2 years ago
7 0
D is the answer Multiply 15 times 30 and divide by 2.25
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what is the slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of 3/4?
Troyanec [42]
Y = mx + b
slope(m) = 3/4
(5,-4)...x = 5 and y = -4
now we sub
-4 = 3/4(5) + b
-4 = 15/4 + b
-4 - 15/4 = b
-16/4 - 15/4 = b
- 31/4 = b....or - 7 3/4 = b

so ur equation is : y = 3/4x + (-31/4) or y = 3/4x - 31/4
3 0
2 years ago
lighting if a 25-foot-tall house cast a 75-foot shadow at the same time that a streetlight casts a 60-foot shadow how tall is th
jolli1 [7]

Answer:

The street light is 20 feet tall.

Step-by-step explanation:

This question depends on a proportion. Keep your height of the object in one ratio and the length of the shadow in the other.

25/x = 75/60      Notice the height of the structure is on the left. The length of the shadow is on the right. Cross multiply

75x =  60 * 25     Combine the right

75x = 1500          Divide by 75

x = 1500/75

x = 20

The street light is 20 feet tall.

3 0
2 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
2 years ago
Solve the inequality.
Dima020 [189]

Answer:

Step-by-step explanation:

x + 8 < - 28

x < - 28 - 8

x < - 36

Option A is the correct answer

3 0
2 years ago
Find the sum: (3x^2+2x+3)+(x^2+x+1)
elena-s [515]

Answer:

 4x2 + 3x + 4

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant   4 • 4 = 16

Step-2 : Find two factors of  16  whose sum equals the coefficient of the middle term, which is   3 .

-16+-1=-17

-8+-2=-10

-4+-4=-8

-2+-8=-10

-1+-16=-17

1+16=17

2+8=10

4+4=8

8+2=10

16+1=17

Final result :

4x2 + 3x + 4

3 0
2 years ago
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