Answer this question for brainliest
2 answers:
As checked on Desmos (see photo attached) the answer should be:
Y= -7x + 26
To get this, I first plotted the points (4,-2) and (2,5). I then did rise over run, and counted how far down and how far to the right the points changed, and I got -7/1. Finally, To find the y-intercept, I plugged in numbers starting from 0 until I was able to make a slope of a line that lined up with the points.
Hope this helps :)
Y= -7x + 26
To get this, I first plotted the points (4,-2) and (2,5). I then did rise over run, and counted how far down and how far to the right the points changed, and I got -7/1. Finally, To find the y-intercept, I plugged in numbers starting from 0 until I was able to make a slope of a line that lined up with the points.
Hope this helps :)
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The z-score of the speed value gives the measure of dispersion of the from
the mean observed speed.
The probability that the speed of a car is between 63 km/h and 75 km/h is
<u>0.273</u>.
The given parameters are;
The mean of the speed of cars on the highway, = 60 km/h
The standard deviation of the cars on the highway, σ = 5 km/h
Required:
The probability that the speed of a car is between 63 km/h and 75 km/h
Solution;
The z-score for a speed of 63 km/h is given as follows;
Which gives;
From the z-score table, we have;
P(x < 63) = 0.7257
The z-score for a speed of 75 km/h is given as follows;
Which gives, P(x < 75) = 0.9987
The probability that the speed of a car is between 63 km/h and 75 km/h is therefore;
P(63 < x < 75) = P(x < 75) - P(x < 63) = 0.9987 - 0.7257 = 0.273
The probability that the speed of a car is between 63 km/h and 75 km/h is
<u>0.273</u>.
Learn more here:
Answer:
a)0.08 , b)0.4 , C) i)0.84 , ii)0.56
Step-by-step explanation:
Given data
P(A) = professor arrives on time
P(A) = 0.8
P(B) = Student aarive on time
P(B) = 0.6
According to the question A & B are Independent
P(A∩B) = P(A) . P(B)
Therefore
&
is also independent
= 1-0.8 = 0.2
= 1-0.6 = 0.4
part a)
Probability of both student and the professor are late
P(A'∩B') = P(A') . P(B') (only for independent cases)
= 0.2 x 0.4
= 0.08
Part b)
The probability that the student is late given that the professor is on time
=
=
= 0.4
Part c)
Assume the events are not independent
Given Data
P = 0.4
= = 0.4
= 0.4 x P
= 0.4 x 0.4 = 0.16
= 0.16
i)
The probability that at least one of them is on time
= 1-
= 1 - 0.16 = 0.84
ii)The probability that they are both on time
P = 1 -
= 1 -
= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56
Answer:
Mr. Chang will have 15714.90 dollars.
Step-by-step explanation:
p = 650
r =
Number of periods or n =
Future value formula is :
Putting the values in formula we get;
= $15714.90
Hence, Mr. Chang will have 15714.90 dollars.