Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
Answer:
x = 88/45
Step-by-step explanation:
square of tangent segment = produce of entire secant and segment of secant outside circle
(GH)² = GS × GW
(13)² = 9(5x + 9)
169 = 45x + 81
45x = 88
x = 88/45
C=1.56n
Should give the the total price of n pounds of blackberry
Blankets:$32
Towels:$16
You set it up as a system of equations.
I made the blankets x and the towels y.
You get 2 equations:
21x+21y=1008
21x+ 23y= 1040
I solved the system by solving the second equation for 21 x
21x= 1040-23y
And plugged it into the first equation
1040-23y+21y=1008
Y= 16
Then I plugged 16 in for y:
21x+23(16)=1040
X=32