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Brrunno [24]
3 years ago
5

Suppose that the probabilities of a customer purchasing​ 0, 1, or 2 books at a book store are 0.4​, 0.2​, and 0.4​, respectively

. What is the expected number of books a customer will​ purchase?
Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

Expected number of books = 1.0

Step-by-step explanation:

Expected number of books, E(x) = ∑xp(x)

∑ = Summation

x = books

p(x) = probability of purchasing a book

E(x) = (0*0.4) + (1*0.2) + (2*0.4)

E(x) = 0 + 0.2 + 0.8 = 1.0

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Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

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Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

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In the same manner we can look at the y components of those points to find the vertical displacement

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Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

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Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

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Which give us

\theta = 39.3^\circ

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Step-by-step explanation:

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