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Brrunno [24]
3 years ago
5

Suppose that the probabilities of a customer purchasing​ 0, 1, or 2 books at a book store are 0.4​, 0.2​, and 0.4​, respectively

. What is the expected number of books a customer will​ purchase?
Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

Expected number of books = 1.0

Step-by-step explanation:

Expected number of books, E(x) = ∑xp(x)

∑ = Summation

x = books

p(x) = probability of purchasing a book

E(x) = (0*0.4) + (1*0.2) + (2*0.4)

E(x) = 0 + 0.2 + 0.8 = 1.0

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LiRa [457]

Answer:

1.8% or 1.818181%

Step-by-step explanation:

If in a batch of 440 water purifiers, we find 8 to be defective.

Then the probability of the next purifier being defective is 8/440

In percentage = 8/440 * 100

=> 8/44 * 10

=> 8/22 * 5

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=> 20 / 11

20/11 is roughly 1.8181818

Rounding it to the nearest tenth, we get 1.8%

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3 years ago
Pure copper was mixed with a 10% copper alloy to produce an alloy thát was 25% copper. How much of the pure copper and how much
lora16 [44]

Answer:

6kg pure copper and 30 kg 10% copper was mixed to give 36kg of 25% alloy

Step-by-step explanation:

Here, we want to produce 36 kg of 25% alloy

Let the Pure copper be x kg while 10% alloy be y kg

Pure copper is simply 100% copper

Thus;

x + y = 36 •••••(i)

Then;

100% of x + 10% of y = 25% of 36

= x + 0.1y = 9 •••••• ii)

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Equate both x

36-y = 9-0.1y

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0.9y = 27

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Step-by-step explanation:

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