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zloy xaker [14]
3 years ago
14

PLZZZZZZZZZZZZZZZZZ HELP!

Mathematics
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

-8

Step-by-step explanation:

5(x+12)=  20

5x+60= 20  

5x= -40

x= -8

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A student wanted to construct a 95% confidence interval for the average age of students in her statistics class. She randomly se
Darina [25.2K]

Answer: (17.42, 20.78)

Step-by-step explanation:

As per given , we have

Sample size : n= 9

\overline{x}=19.1 years

Population standard deviation is not given , so it follows t-distribution.

Sample standard deviation : s= 1.5 years

Confidence level : 99% or 0.99

Significance level : \alpha= 1-0.99=0.01

Degree of freedom : df= 8  (∵df =n-1)

Critical value : t_c=t_{(\alpha/2,\ df)}=t_{0.005,\ 8}= 3.355

The 99% confidence interval for the population mean would be :-

\overline{x}\pm t_c\dfrac{s}{\sqrt{n}}

19.1\pm (3.355)\dfrac{1.5}{\sqrt{ 9}}\\\\=19.1\pm1.6775\\\\=(19.1-1.6775,\ 19.1+1.6775)\\\\=(17.4225,\ 20.7775)\approx(17.42,\ 20.78)

Hence, the 99% confidence interval for the population mean is (17.42, 20.78) .

7 0
3 years ago
Five divided sixty eight
Schach [20]
5/68, or about 0.07                                                              
8 0
2 years ago
What is the answer to this
Softa [21]

Answer:

5 f

Re-order terms so that constants are on the left

. 5

5 f

solution

5 f

7 0
2 years ago
Simplify: square root 27x12 over 300x8
alex41 [277]

Answer:

10

-------------

3x^2

Step-by-step explanation:

First lets simplify what is inside the square root

300x8

---------------

27x12

3 * 100 x^8

------------------

3 *9 x^12

The 3's cancel  and we know a^b/ a^c = a^(b-c)

100/9 x^ (8-12)

100/9 x^-4

sqrt( 100/9 x^-4)

Put the negative exponent in the denominator and make it positive

sqrt( 100 / (9x^4) )

We know that sqrt( a / b) = sqrt(a) / sqrt( b)

sqrt(100)

----------------

sqrt( 9x^4)

10

-------------

3x^2

Read more on Brainly.com - brainly.com/question/12900964#readmore

5 0
3 years ago
If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

#SPJ10

5 0
2 years ago
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