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Vika [28.1K]
3 years ago
15

Please help!!!! I need it quick!!!!

Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

f(4) = 49

f(-3) = -35

Step-by-step explanation:

f(4) = 12(4) + 1 = 48 + 1 = 49

f(-3) = 12(-3) + 1 = -36 + 1 = -35

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Is 8/10 greater than 3/4
makvit [3.9K]

Answer:

yes it is

8/10 = 80%

3/4 = 75%

Step-by-step explanation:

5 0
3 years ago
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Solve each of the following literal equations for c: (c/b) - x = 2d and ac + bd = x
maks197457 [2]
(c/b) - x = 2d
(c/b) = 2d + x
c = b(2d + x)
c = 2db + bx

ac + bd = x
ac = x - bd
c = (x - bd) / a OR c = (x/a) - (bd/a)
8 0
3 years ago
Rhombus EFGH is shown. What is the measure of ∠HGJ?
MaRussiya [10]

Answer:

∠HGJ = 35°

Step-by-step explanation:

Although the question is somewhat incomplete, I have tried to reconstruct the question as much as possible to aid understanding (attached is the pictorial representation of the rhombus).

Firstly, it is important to note that rhombuses are parallelograms which have all sides equal and whose diagonals are perpendicular to each other. In addition to this, their diagonals bisect one other.

Mathematically, |EF| = |FG| = |GH| = |HE|

Another property which rhombuses have is that their opposite angles are equal.

Mathematically, ∠E = ∠G, ∠H = ∠F

The adjacent angles in a rhombus are supplementary. This means that the sum of angles closest to each other is 180°.

Mathematically, ∠E + ∠F = 180°, ∠F + ∠G = 180°, ∠G + ∠H = 180°,

∠H + ∠E = 180°

The question gave us ∠GHE and asked us to find ∠HGJ (denoted as θ in the picture attached). Note that ∠GHE means ∠H. That is, ∠GHE ⇒ ∠H

∠GHE or ∠H = 110°

From the properties of rhombuses (earlier stated), we know that adjacent angles in a rhombus are supplementary

Mathematically,

∠GHE + ∠FGH ⇒ 110° + ∠FGH = 180° ⇒ ∠FGH = 180° - 110°

∠FGH or ∠G = 70°

To calculate for ∠HGJ, we divide ∠FGH by 2, we have:

∠HGJ = ∠FGH ÷ 2 = 70° ÷ 2

∠HGJ = 35°

3 0
2 years ago
Solve the equation by elimination <br> 2x - 5y = -7<br> =<br> -2x + 3y = 1
seropon [69]

Answer:

Step-by-step explanation:

5 0
1 year ago
Which rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C'?
ANEK [815]
From the figure, it can be seen that the mage A'B'C' is obtained from the pre-image ABC by translating/shifting the vertices of the image by 7 units to the right and 6 units down.

Therefore, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is <span>(x, y) → (x + 7, y – 6)</span>.
6 0
3 years ago
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