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Sauron [17]
2 years ago
10

2. ART An artist created a statue in the shape of a

Mathematics
1 answer:
son4ous [18]2 years ago
8 0

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

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The simple interest on a certain sum of money is 3/8 of the the sum after 6 1/4 years. Find the the rate per cent charged.
Masja [62]
Time= 6 1/4= 25/4
Principal- Rs x
Rate=?
Rate=100 * Simple Interest
Rate= 100*3x*4 divided by x*8*25
Rate=6%
3 0
2 years ago
Find the value of y in the solution to the system of equations shown.<br> y= 12x+7<br> y=-6x+25
padilas [110]

Answer:  The required value of y is 19.

Step-by-step explanation:  We are given to find the value of y in the solution to the following system of equations :

y=12x+7~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=-6x+25~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Comparing equations (i) and (ii), we get

12x+7=-6x+25\\\\\Rightarrow 12x+6x=25-7\\\\\Rightarrow 18x=18\\\\\Rightarrow x=\dfrac{18}{18}\\\\\Rightarrow x=1.

From equation (i), we get

y=12\times1+7=12+7=19.

Thus, the required value of y is 19.

4 0
3 years ago
Read 2 more answers
H(x) = x^2 + 1 k(x) = x – 2<br> (h + k)(2)=?
likoan [24]
First we will compute the h+k and then multiply the result by 2.
To add polynomials, we add terms whose variables are alike, for example:
we add the coefficients of x^2 together, the coefficients of x together and so on.

Therefore:
h + k = x^2 + 1 + x - 2 = x^2+x-1

Now, we will multiply this answer by 2 to get the final answer:
2(h+k) = 2(x^2+x-1) = 2x^2 + 2x -2
6 0
3 years ago
(P+a)(V+b)=c,
UNO [17]

Answer:

PUSHIN

Step-by-step explanation:

6 0
2 years ago
The half-life of a certain substance is 20 years. How much of a 100 gram sample will be left after 20 years?
cluponka [151]

\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &100\\ t=\textit{elapsed time}\dotfill &20\\ h=\textit{half-life}\dotfill &20 \end{cases} \\\\\\ A=100\left( \frac{1}{2} \right)^{\frac{20}{20}}\implies A=100\left( \frac{1}{2} \right)^1\implies A=50

5 0
3 years ago
Read 2 more answers
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