Question

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Hello and Good Morning/Afternoon

Let's take this problem step-by-step:

To find the solution to a system of equation

  ⇒ must set the equations equal to each other

     ⇒ and solve

Let's put that into action

  $x^2-2x+3 = -2x + 12\\x^2-2x+2x+3-12=0\\x^2-9=0\\(x+3)(x-3)=0$

• At this point, to make the whole thing equal zero

          ⇒ either 'x+3' or 'x-3' equals zero

              ⇒ must find 'x' that satisify either equation

                    $x-3=0\\x=3\\\\x+3=0\\x=-3$

Let's find the corresponding f(x) to each x-value

  $f(3) = -2(3)+12=-6+12 = 6\\\\f(-3) = -2(-3) + 12=6+12=18$

Therefore the solutions are (3,6) and (-3,18)

Answer: (3,6), (-3,18)

Hope that helps!

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