The dimensions of the square base after cutting the corners will be (40-2x). The depth of the box will be x, so its volume is given by
V = x(40-2x)²
You can differentiate this to get
V' = 12x² -320x -1600
Setting this to zero and factoring gives
(3x-20)(x-20) = 0
The appropriate choice of solutions is
x = 20/3 = 6 2/3
The
dimensions of the box of maximum volume are
26 2/3 in square by 6 2/3 in deepThe
maximum volume is
(80/3 in)²(20/3 in) =
4740 20/27 in³
Peers if not of similar circumstances may be biased or not understand the situation as well.
Answer:
A. 23+x=140
Step-by-step explanation:
The angle addition postulate states that the measure of a larger angle formed by two or more smaller angles placed side by side is the the sum of the smaller angles. The angle addition postulate states that if B is in the interior of AOC , then:
m∠AOB + m∠BOC = m∠AOC.
From the image:
∠NOP = ∠NOQ + ∠QOP
∠NOP = 140, ∠NOQ = x, ∠QOP = 23
substituting:
140 = x + 23
x = 140 - 23 = 117
∠NOQ = 117°
Answer:
Step-by-step explanation:
11 is A ( i think)
12 i know is c but if wrong im so sorry
hope this helps
What are we supposed solve for? Be for specific please