Answer:
e. 0.0072
Step-by-step explanation:
We are given that a bottling company uses a filling machine to fill plastic bottles with cola. And the contents vary according to a Normal distribution with Mean, μ = 298 ml and Standard deviation, σ = 3 ml .
Let Z = 
~ N(0,1) where, Xbar = mean contents of six randomly
selected bottles
n = sample size i.e. 6
So, Probability that the mean contents of six randomly selected bottles is less than 295 ml is given by, P(Xbar < 295)
P(Xbar < 295) = P( < 
) = P(Z < -2.45) = P(Z > 2.45)
Now, using z% score table we find that P(Z > 2.45) = 0.00715 ≈ 0.0072 .
Therefore, option e is correct .
<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
I'll write in the format (x;y) where x is the salad dressings amount, and y is the amount of servings.
We can see the line goes through the points (1;2) , (2;4) , (3;6) ...
So, the amount of servings are doubled the amount of salad dressings she need to use. (1 cup every 2 servings, 2 cups every 4 servings, etc.)
-> Leslle used half a cup of salad dressing for every serving of salad (B)
Answer:
Step-by-step explanation:
Answer:
y=1/2x
Step-by-step explanation:
