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Alecsey [184]
3 years ago
6

An object is launched straight up into the air at an initial velocity of 64 feet per second it is launched from a height of 6 fe

et off the ground. Its height H, in feet, at seconds is given by the equation h= -16t 2+64r +6
Mathematics
1 answer:
blondinia [14]3 years ago
8 0
H is 24 You’re very welcome
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The table shows the distance Randy drove on one day of her vacation
horsena [70]
Given the table showing the distance Randy drove on one day of her vacation as follows:

\begin{tabular}
{|c|c|c|c|c|c|}
Time (h)&1&2&3&4&5\\[1ex]
Distance (mi)&55&110&165&220&275
\end{tabular}

The rate at which she travels is given by

rate= \frac{distance}{time}  \\  \\ = \frac{55}{1} =55mi/h

If Randy has driven for one more hour at the same rate, the number of hours she must have droven is 6 hrs and the total distance is given by

distance = 55 x 6 = 330 miles.
4 0
3 years ago
Which of the following values is a solution of |2-x| less than 4
morpeh [17]

The correct answer is -1.

In order to solve this, we need to split into the positive and negative version of the answers. Let's start with the positive version.

2 - x < 4

-x < 2

x > -2 ----> NOTE: When we divide by -1, we have to change the direction of the sign.

Now we'll do the negative version.

2 - x > -4

-x > -6

x < 6

So we know the number must be greater than -2, but less than 6. The only number on this list that fits that is -1.

4 0
3 years ago
PLEASE HELP ME ON THIS AND SHOW UR WORK<br> THX
swat32
When an exponential function is given as 
f(x)=ab^x, and
knowing that b^0=1, that means that
f(0)=ab^0=a  value of function when x=0, or the initial value.
In the case of
f(x)=20.b^x, f(0)=20.b^0 = 20  (initial value)

If b=1.2, then the hourly growth rate is (1.2-1)=0.2=20%.
If b=1.85, then the hourly growth rate is (1.85-1)=0.85=85%. 
4 0
3 years ago
Which of the following equations have no solutions?
azamat

Answer:

A, B & D

Step-by-step explanation:

Because if you subtract one of the constants from both sides then you should only have equal variables. In other words, both sides have to be identical in this situation.

33x-33= 33x + 25

33x = 33x + 58 No matter what you make x, the right will be 58 bigger than the right so there is no solution.

33x+33=33x+25

33x+8= 33x nope no solution

33x+25=33x+25

33x = 33x both sides identical so there is a solution

33x-25 = 33x +25

33x= 33x+50

4 0
3 years ago
I need help with these two problems. [9 and 10] FORMULAS GIVEN!!
zaharov [31]
<h2>Question 9:</h2>

1. Use Pythagorean Theorem (a²+b²=c²) to solve for missing side of triangle and rectangle. x²+16²=20², or x²+256=400. So, x²=144, and x=12

2. Use formula: 1/2(h)(b1+b2). 1/2 (12) (30+14).

3. Simplify: 1/2 (12) (44)=1/2(528)=264

Area of whole figure is 264 square mm.

<h2>Question 10:</h2>

Literally same thing but with trigonometry.

1. Use sine to find out length of dotted line: sin(60°)=x/12

2: Simplify: 12*sin(60°)=x. x≈10.4 (rounded to the nearest tenth)

3. Use Pythagorean Theorem to find out last leg of triangle: 10.4²+x²=12²

4: Simplify: 108.16 +x²=144. x²=35.84 ≈ 6

5: Use formula: 1/2(h)(b1+b2). 1/2 (10.4) (30+36)

6: Simplify: 1/2 (10.4) (66) =343.2

7: Area of figure is about 343.2

Remember, this is an approximate answer with rounding, so it might not be what your teacher wants. The best thing to do is do it yourself again.

4 0
3 years ago
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