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3 years ago

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An object is launched straight up into the air at an initial velocity of 64 feet per second it is launched from a height of 6 fe

et off the ground. Its height H, in feet, at seconds is given by the equation h= -16t 2+64r +6

1 answer:

blondinia [14]3 years ago

8 0

H is 24 You’re very welcome

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