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Ivan
4 years ago
12

Need help ASAP please

Mathematics
2 answers:
balu736 [363]4 years ago
3 0

Answer:

y{3}

Hope this helped! Stay safe! Peace!✌

andriy [413]4 years ago
3 0

Answer:

2 y^3

Step-by-step explanation:

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Isaac keeps track of the amount of money in his savings certificate each month. He has accumulated the following data:
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d. The common ratio is 1.1

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To see if the data has a common ratio or common difference, we have to see if the division between them is equal(common ratio), or if the difference between them is equal(common difference).

In this case, since 60.5 - 55 \neq 55 - 50, it has a common ratio.

To find it, we divide consecutive terms. For example:

\frac{55}{50} = 1.1

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d. The common ratio is 1.1

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Step 1: −8x2−15x+2

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2. Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79. What did it cost 10 years ago? How long
Makovka662 [10]

Answer:

It cost $0.91 10 years ago.

It takes 10.24 years for the cost of bread to double.

Step-by-step explanation:

The equation for the price of bread after t years has the following format:

P(t) = P(0)(1+r)^{t}

In which P(0) is the current price, and r is the inflation rate, as a decimal.

If we want to find the price for example, 10 years ago, we find P(-10).

Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79.

This means that r = 0.07, P(0) = 1.79. So

P(t) = P(0)(1+r)^{t}

P(t) = 1.79(1+0.07)^{t}

P(t) = 1.79(1.07)^{t}

What did it cost 10 years ago?

P(-10) = 1.79(1.07)^{-10} = 0.91

It cost $0.91 10 years ago.

How long before the cost of the bread doubles?

This is t for which P(t) = 2P(0) = 2*1.79. So

P(t) = 1.79(1.07)^{t}

2*1.79 = 1.79(1.07)^{t}

(1.07)^{t} = 2

\log{(1.07)^{t}} = \log{2}

t\log{1.07} = \log{2}

t = \frac{\log{2}}{\log{1.07}}

t = 10.24

It takes 10.24 years for the cost of bread to double.

5 0
3 years ago
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