Find all the zeros of the polynomial function. f(x)=x^4+62^2+128x+65 I want to find the zeros of the polynomial function
1 answer:
You might be interested in
Answer:
v=a+ 2e1= [3 1 1 1] .
Step-by-step explanation:
Let a = and we know that
=±║α║₂= 2.
As we have gone over in class, the formula for v is v= a-e1
with the sign of chosen to avoid subtraction. This gives v=a+ 2e1= [3 1 1 1] .
Disclaimer ;The question is incomplete
Question:
Determine the Householder transformation that annihilates all but the first entry of the vector[1 1 1 1]>Specifically, if
==
what are the values of α and v?
#SPJ4
learn more about it on
Answer:
D(6, 3)
Step-by-step explanation:
The diagonals of a rectangle bisect each other, so the midpoint of AC is the same as the midpoint of BD. This means ...
(A +C)/2 = (B +D)/2 . . . . the midpoints are the same
A +C = B +D . . . . . . . . . multiply by 2
D = A +C -B = (2+5-2, 1+5-3) . . . . . solve for D, substitute given coordinates
D = (6, 3)
