Answer:
Option C is correct.
Step-by-step explanation:
We need to find reference angle and signs of sinФ, cosФ and tanФ
We know that 
is equal to 150°
and 150° is in 2nd quadrant.
So, Ф is in 2nd quadrant.
And In 2nd quadrant sine is positive, while cos and tan are negative
The reference angle Ф' is found by: π - Ф
=> Ф = 5π/6
so, Reference angle Ф' = π - 5π/6
Ф' = 6π - 5π/6
Ф' = π/6
So, Option C Θ' = pi over 6; sine is positive, cosine and tangent are negative is correct.
The answer would be
4d+2.75p=12
Y=5/2 should be the answer
Answer:
3x + 2y =18
Y= -2/3x + 12
3x + 2(-2/3x+12) = 18
3x + (-4/3x+24) = 18
3x + -1 1/3x +24 =18
1 2/3x +24 = 18
1 2/3x = -6
5/3x = -6
x = -3.75
Step-by-step explanation:
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
