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Alex_Xolod [135]
3 years ago
14

Which of the following is the equation of the line graphed below?

Mathematics
1 answer:
Masteriza [31]3 years ago
4 0

The line crosses the y-axis at y=4, so will have an equation of the form

... y = (something)·x + 4


The line rises from left to right, so has a positive slope. That is, the "(something)" must be greater than zero.


The only selection that meets these criteria is

... B y = 2x + 4

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When Θ = 5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent? Θ' = negative pi over 6; s
timama [110]

Answer:

Option C is correct.

Step-by-step explanation:

\theta=\frac{5\pi }{6}

We need to find reference angle and signs of sinФ, cosФ and tanФ

We know that \theta=\frac{5\pi }{6}radians is equal to 150°

and 150° is in 2nd quadrant.

So, Ф is in 2nd quadrant.

And In 2nd quadrant sine is positive, while cos and tan are negative

The reference angle Ф' is found by: π - Ф

=> Ф = 5π/6

so, Reference angle Ф' = π - 5π/6

Ф' = 6π - 5π/6

Ф' = π/6

So, Option C Θ' = pi over 6; sine is positive, cosine and tangent are negative is correct.

5 0
3 years ago
PLEASE HELPPP MEEEEEEEEEEEEEEE
Papessa [141]
The answer would be

4d+2.75p=12
7 0
3 years ago
Read 2 more answers
What is the value of y in the equation 5x+2y=20, when x=0.3
salantis [7]
Y=5/2 should be the answer
5 0
3 years ago
What is the solution of the system <br> 3x + 2y =18 <br> Y= -2/3x + 12
laiz [17]

Answer:

3x + 2y =18


Y= -2/3x + 12

3x + 2(-2/3x+12) = 18

3x + (-4/3x+24) = 18

3x + -1 1/3x +24 =18

1 2/3x +24 = 18

1 2/3x = -6

5/3x = -6

x = -3.75

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)
Paraphin [41]
This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c
 
<u>c = 1
</u>
<u /><u />
If c =1,

6 = a + 1
<u>a = 5
</u>
<u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?




5 0
3 years ago
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