Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
The answer to your question i think is b
Answer:
9 and 4/5
Step-by-step explanation:
Answer:
- (-6, 10)
- (-10, 9)
- (-11, -6)
- (-5, 1)
Step-by-step explanation:
<em>(x,y) → (x-8, y+4)</em>
1. (2, 6)
(2-8, 6+4)
<u>(-</u><u>6, 10)</u>
2. (-2, 5)
(-2-8, 5+4)
<u>(-10, 9)</u>
3. (-3, -10)
(-3-8, -10+4)
<u>(-11, -6)</u>
ídk man u should connect it to <u>(11, -7)</u> since it's the only choice closest to the right answer, but If u can write the correct then write this. there's prolly an error in that quiz ídk
4. (3, -3)
(3-8, -3+4)
<u>(-5, 1)</u>
<u> </u>still not in the choices nanii but <u>(5, -14)</u> is the only choice left and also the closest, and even if u use calculator the correct answer is still (-5, 1). sigh, I hope this helper at least
