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2 years ago

Joe made a scale drawing of the community pool in his town.

Mathematics

1 answer:

Effectus [21]2 years ago

8 0

Answer:

The length of the pool is 28 meters and the width of the pool is 10.5 meters.

Step-by-step explanation:

In the scale drawing of Joe, the community pool has (length : width) = 8 : 3

Let the actual length of the pool is 8x meters and the actual width is 3x meters.

Now, given that the actual pool has a perimeter of 77 meters.

So, 2(8x + 3x) = 77

⇒ 22x = 77

⇒ x = 3.5

So, the length of the pool is 8x = 8(3.5) = 28 meters and the width of the pool is 3x = 3(3.5) = 10.5 meters. (Answer)

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A secant and a tangent to a circle intersect in a 42-degree angle. The two arcs of the circle intercepted by the secant and the

Amanda [17]

Answer:

The measure of the third arc is $150\°$

Step-by-step explanation:

step 1

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

in this problem

Let

x----> the greater arc of the circle intercepted by the secant and the tangent

y----> the smaller arc of the circle intercepted by the secant and the tangent

$42\°=\frac{1}{2}(x-y)$

$84\°=(x-y)$ ----> equation A

$\frac{x}{y}=\frac{7}{3}$

$x=\frac{7}{3}y$ -----> equation B

Substitute equation B in equation A and solve for y

$84\°=(\frac{7}{3}y-y)$

$84\°=(\frac{4}{3}y)$

$y=3*84\°/4=63\°$

Find the value of x

$x=\frac{7}{3}(63\°)=147\°$

step 2

Find the measure of the third arc

Let

z------> the measure of the third arc

we know that

$x+y+z=360\°$ -----> complete circle

substitute the values and solve for z

$147\°+63\°+z=360\°$

$z=360\°-(147\°+63\°)=150\°$

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3 years ago

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Ainat [17]

Answer:

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Step-by-step explanation:

Implying the x and y coordinates, you get this.

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3 years ago

What’s are the answers for both?

nevsk [136]

Answer:

Step-by-step explanation:

8d + 4 = 5d + 28

Group like terms

That's

8d - 5d = 28 - 4

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Divide both sides by 3

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Cross multiply

we have

7(7g + 8) = 38.5(4)

49g + 56 = 154

49g = 154 - 56

49g = 98

Divide both sides by 49

g = 2

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3 years ago

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Answer:

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2 years ago

A carnival game has 3 identical boxes. The boxes have the following amounts of money: one has $30.00, one has $6.00, and one has

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$200 divided by 100 customers = 2$.

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