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Daniel [21]
4 years ago
8

Which molecule is an aromatic hydrocarbon? Two central carbons are double bonded to each other; the pair is single bonded to C H

3 above left and right, and to H below left and right. A skeletal model has line segments that slant up, down, up, and up again in a triple bond. Two hexagon rings with carbons at each corner have alternating double bonds and share one side. H is single bonded to all the C's except the ones on the shared side. Two carbons are triple bonded to each other; each has a single bond to the outside.
Chemistry
1 answer:
Tju [1.3M]4 years ago
4 0

Answer:

C. Two hexagon rings with carbons at each corner have alternating double bonds and share one side. H is single bonded to all the C's except the ones on the shared side

Explanation:

The structure of aromatic hydrocarbon contain benzene (C6H6) which is a cyclic hydrocarbon.

Alternating single and double bond at each corner of two hexagon rings is an aromatic hydrocarbon as the alternating single and double bond form a benzene ring and H is single bonded to all the carbon's (C) except on the shared side.

Hence, the correct answer is "C"

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Please help! ill give you 90 points!
Luba_88 [7]

Answer:

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Explanation:If this helped subscribe to Amiredagoat Yt

3 0
3 years ago
Compare homogeneous and heterogeneous mixtures?
Gemiola [76]
A homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly different substances.
8 0
3 years ago
Help!
GarryVolchara [31]

I'm pretty certain the answer is 2) because fluorine is a diatomic gas meaning it travels with 2 molecules (simplified). It is a gas so molecules should also be spread out so the answer cannot be 3) or 4).

Hope this helps! :)

8 0
3 years ago
A 100 gram block is placed on a scale that is known to have a 12% error. What will the scale read?
sesenic [268]

The scale will read <u>112 grams.</u>

Why?

Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:

ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g

We can see that the scale will read 112 grams.

Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:

PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)

Hence, we can see that the scale will read <u>112 grams.</u>

Have a nice day!

7 0
4 years ago
Sugar C12 H22 011 can be classified as a element, heterogeneous mixure, solution, compound​
Fantom [35]

Answer:

The answer is a compound.

it is a compound as it contains different elements

Explanation:

5 0
3 years ago
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