Moles of ZnSO4 = Mass/Mr
= 2/(65.4 + 32.1 + (16 x 4))
= 0.012383.... mol
Since there is no chemical equation provided, I will assume that the ratio of ZnSO4:Li2CO3 is 1:1
Therefore there are 0.012383 mil of Li2SO4 as well
So the mass would be Moles x Mr = 0.012383.... x ((6.9 x 2) +32.1 + (4x16))
= 1.360 g of Li2SO4 produced
Answer:
![\lambda=0.03\ m](https://tex.z-dn.net/?f=%5Clambda%3D0.03%5C%20m)
Explanation:
Given that,
The frequency of a the microwaves is ![1\times 10^{10}\ Hz](https://tex.z-dn.net/?f=1%5Ctimes%2010%5E%7B10%7D%5C%20Hz)
We need to find the wavelength. Al electromagnetic wave travel with speed of sound. We know that,
![v=f\lambda\\\\\text{Where}\ \lambda\ \text{is the wavelength of microwaves}\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{3\times 10^8}{10^{10}}\\\\\lambda=0.03\ m](https://tex.z-dn.net/?f=v%3Df%5Clambda%5C%5C%5C%5C%5Ctext%7BWhere%7D%5C%20%5Clambda%5C%20%5Ctext%7Bis%20the%20wavelength%20of%20microwaves%7D%5C%5C%5C%5C%5Clambda%3D%5Cdfrac%7Bv%7D%7Bf%7D%5C%5C%5C%5C%5Clambda%3D%5Cdfrac%7B3%5Ctimes%2010%5E8%7D%7B10%5E%7B10%7D%7D%5C%5C%5C%5C%5Clambda%3D0.03%5C%20m)
So, the wavelength of the microwaves is 0.03 m.
Answer:
If n=1, l can only have the value l=0 and the total number of orbitals is 0. If l=1, ml can be -1,0 or 1 and the total number of orbitals at l=1 is 3.
Explanation:
When solving the radial part of Schrödinger equation, one needs to expand in power series that lead to Laguerre polynomials of the form
, being n and l the quantum numbers. As is known, in the Laguerre polynomials the subindex must be greater than or equal to 0, which implies
. So if n=1, the only possible value of l is l=0.
Likewise, when solving the angular part, one gets the spherical harmonics
can be
. Therefore the sublevel l=| has 3 possible orbitals.
I would say A but if it’s wrong I’m sorry
It looks like a bunch of squares. Lolb