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bixtya [17]
2 years ago
9

An unknown gas effuses at a rate of 2.0 times the rate of Cl₂. What is the molar mass of the unknown gas?

Chemistry
1 answer:
Ratling [72]2 years ago
3 0

The molar mass of the unknown gas is determined as 17.75 g.

<h3>Rate of gas diffusion</h3>

The rate of gas diffusion is given by Graham's law.

R₁√M₁ = R₂√M₂

where;

  • R₁ is the rate of diffusion of the unknown gas
  • M₁ is the molecular mass of the unknown gas
  • R₂ is rate of diffusion of chlorine gas
  • M₂ is the molecular mass of chlorine gas

\frac{R_1}{R_2} = \sqrt{\frac{M_2}{M_1} } \\\\\frac{2R_2}{R_2} = \sqrt{\frac{71}{M_1} }\\\\2 = \sqrt{\frac{71}{M_1} }\\\\2^2 = \frac{71}{M_1} \\\\M_1 = \frac{71}{4} \\\\M_1 = 17.75 \ g

Learn more about rate of diffusion here:  brainly.com/question/11197959

#SPJ1

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How do starch and ATP store and supply energy?
NeX [460]

Answer:

Explanation:

ATP is used for immediate energy and short-term storage, while starch molecules are stable and can be stored for a long time

ATP is used for immediate energy and long-term storage, while starch molecules are unstable and can be stored for a short amount of time.

8 0
3 years ago
Name the phase change in each of these events: (c) Wet clothes dry on a summer day
8090 [49]

The phase change occurs during evaporation. On a hot day, wet clothing is drying. A liquid becomes a gas when it evaporations.

During the process of evaporation, a liquid transforms into a gaseous phase that is not saturated with the evaporating substance. The term "vaporization of a liquid" refers to this process. Clothes start to dry as water vapor escapes from the fabric's surface.

<h3>What is evaporation?</h3>

A liquid turns into a gas through the process of evaporation. Raindrops that "vanish" on a hot day or damp clothing that dries in the sun are good examples of the phenomena. In these instances, the liquid water is evaporating into a gas known as water vapor rather than really dissipating. Global evaporation takes place.

Learn more about evaporation: brainly.com/question/5019199

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5 0
1 year ago
A chemist compresses a 1.8 L sample of carbon dioxide gas at 2.4 atm to a final volume of 1.5 L. Assuming the temperature is con
Eduardwww [97]

Answer:

THE PRESSURE EXERTED BY THE GAS IS THEREFORE 2.88 atm.

Explanation:

Boyle's law states that at constant temperature, the volume of a given mass of gas is inversely proportional to the pressure of the gas.

Mathematically, P1 V1 = P2 V2

Write out the values of the variables given:

P1 = 2.4 atm

V1 = 1.8 L

V2 = 1.5 L

P2 = unknown

Re-arranging the variables by making P2 the subject of the equation, we have:

P2 = P1 V1 / V2

P2 = 2.4 * 1.8 / 1.5

P2 = 2.9=88 atm

Hence, the pressure exerted by the gas is therefore 2.88 atm

5 0
3 years ago
Compare and contrast 10kg of melting ice and 1kg of freezing water address temperature heat flow thermal energy what is the simp
iris [78.8K]

Answer:

10 kg of ice will require more energy than the released when 1 kg of water is frozen because the heat of phase transition increases as the mass increases.

Explanation:

Hello!

In this case, since the melting phase transition occurs when the solid goes to liquid and the freezing one when the liquid goes to solid, we can infer that melting is a process which requires energy to separate the molecules and freezing is a process that releases energy to gather the molecules.

Moreover, since the required energy to melt 1 g of ice is 334 J and the released energy when 1 g of water is frozen to ice is the same 334 J, if we want to melt 10 kg of ice, a higher amount of energy well be required in comparison to the released energy when 1 kg of water freezes, which is about 334000 J for the melting of those 10 kg of ice and only 334 J for the freezing of that 1 kg of water.

Best regards!

7 0
3 years ago
To 225 mL of a 0.80M solution of KI, a student adds enough water to make 1.0L of a more dilute KI solution. What is the molarity
Makovka662 [10]
Hope this helps you!

8 0
3 years ago
Read 2 more answers
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