Answer:
Step-by-step explanation:
Given:
Area = 3x^3 - 16x^2 + 31x - 20
Base:
x^3 - 5x
Area of trapezoid, S = 1/2 × (A + B) × h
Using long division,
(2 × (3x^3 - 16x^2 + 31x - 20))/x^3 - 5x
= (6x^3 - 32x^2 + 62x - 40))/x^3 - 5x = 6 - (32x^2 - 92x + 40)/x^3 - 5x = 2S/Bh - Ah/Bh
= 2S/Bh - A/B
= (2S/B × 1/h) - A/B
Since, x^3 - 5x = B
Comparing the above,
A = 32x^2 - 92x + 40
2S/B = 6
Therefore, h = 1
Answer:
44
Step-by-step explanation:
x + (x+2) + (x+4) + (x+6) + (x+8) + (x+10) = 294
Combine all like terms for x and integers
6x + 30 = 294
Minus 30 on both sides
6x = 264
Divide by 6
x = 44
N-6/n²+11n+24/n+1/n+3
First, we need to factor the following:
n² + 11n + 24 → (n + 3)(n + 8)
n² → n * n
factor of 24 are:
1 x 24
2 x 12
3 x 8 We will use these factors. 3 + 8 = 11
4 x 6
Division involving fractions results to multiplying the first fraction to the reciprocal of the second fraction.
n-6/(n+3)(n+8) * n+3 / n+1 → n+3 is in both numerator and denominator. Cancel each other out.
n-6/n+8 * 1/n+1
n-6/(n+8)(n+1) Correct answer is Choice D.
