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lana66690 [7]
3 years ago
14

Bob and Laquisha have volunteered to serve on the Junior Prom Committee. The names of twenty volunteers,

Mathematics
2 answers:
marishachu [46]3 years ago
6 0

Answer:

Hey there!

1/19 (1/20)=1/380, so the probability is 1/380

Let me know if this helps :)

Law Incorporation [45]3 years ago
3 0

Answer:

1/380

Step-by-step explanation:

<u>Probability of Bob's name drawn first is:</u>

  • 1/20                            as there are 20 people with equal chance

<u>And probability of Laquisha's name drawn second is: </u>

  • 1/19                            as there are 19 people left with equal chance

<u>Probability of the two events happening is: </u>

  • 1/20*1/19 = 1/380       product of individual probabilities
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2 years ago
Write an expression in simplest form the perimeter of the figure ?
kondor19780726 [428]

Answer:

4+11a+8b

Step-by-step explanation:

1) 4+3a+2b+6b+5a+3a

2) 3a+3a+5a=11a. 2b+6b=8b

5 0
2 years ago
Margaret is planning a wedding reception. She wants to spend less than her budget of $5,748, and Margaret has already spent $2,4
noname [10]

Answer:

She can invite 109 guests and be right on top of budget. If she wants to spend less than her budget though she can only invite 108 people.

Step-by-step explanation:

First you have to subtract 5,748 - 2,478 which is 3270. Next you have to divide 3270 by 30 because each person costs 30 dollars. 3270 divided by 30 is 109.

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6 0
3 years ago
The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:
blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

  =\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182

Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

      =\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899

Thus, the standard deviation of the age distribution is 6.2899 years.

7 0
2 years ago
Write the following:<br>a) 16 as a fraction of 152<br>b) 15 as a fraction of 210<br>​
Nesterboy [21]

Answer:

\frac{16}{152}

\frac{15}{210}

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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