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lana66690 [7]
3 years ago
14

Bob and Laquisha have volunteered to serve on the Junior Prom Committee. The names of twenty volunteers,

Mathematics
2 answers:
marishachu [46]3 years ago
6 0

Answer:

Hey there!

1/19 (1/20)=1/380, so the probability is 1/380

Let me know if this helps :)

Law Incorporation [45]3 years ago
3 0

Answer:

1/380

Step-by-step explanation:

<u>Probability of Bob's name drawn first is:</u>

  • 1/20                            as there are 20 people with equal chance

<u>And probability of Laquisha's name drawn second is: </u>

  • 1/19                            as there are 19 people left with equal chance

<u>Probability of the two events happening is: </u>

  • 1/20*1/19 = 1/380       product of individual probabilities
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Given the inequality -8 &lt; 2, explain what happens when you multiply or divide both sides by 2 and what happens when you multi
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Answer:

The inequality sign remains same while multiply or divide both sides by positive numbers.

The inequality sign changes while multiply or divide both sides by negative numbers.

Step-by-step explanation:

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Now, if we multiply 2 in both sides then - 16 < 4

Again, if we divide by 2 into both sides then  - 4 < 1

Therefore, the inequality sign remains the same while multiply or divide both sides by positive numbers.

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And, if we divide -2 into both sides then 4 > -1

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White raven [17]
A = amount invested at 4%.

b = amount invested at 9%.

we know the total amount invested was $26500, thus a + b = 26500.

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how much is 9% of b?  well, is just (9/100) * b, or 0.09b.

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7 0
3 years ago
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timofeeve [1]

Answer:

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2 years ago
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Kitty [74]

Answer:

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Step-by-step explanation:

Given the expression

\log _3\:x^9

now rewriting the expression

\log _3\:x^9

\mathrm{Apply\:log\:rule\:}\log _a\left(x^b\right)=b\cdot \log _a\left(x\right),\:\quad \mathrm{\:assuming\:}x\:\ge \:0

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Therefore,

\log _3\left(x^9\right)=9\log _3\left(x\right)

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