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3 years ago

Jill added 450+790+123 and 1163 .is this sum reasonable? Explain.

Mathematics

2 answers:

N76 [4]3 years ago

6 0

Answer:

The sum given is not reasonable.

Step-by-step explanation:

Given : Jill added 450+790+123 and 1163.

To find : Is this sum reasonable? Explain.

Solution :

To find the correct result we have to add them step by step,

4 5 0

7 9 0

+1 2 3

-----------

13 6 3

So, $450+790+123=1363$

The sum given is not reasonable.

Therefore, The given sum is not correct.

AlexFokin [52]3 years ago

3 0

Let us manually add the given numbers.

450

790

123

____

1363

Therefore we see that the correct answer 1363 which is far from what Jill got which is only 1163.

Therefore the answer is No, the sum should be 1363 (closer to 1400).

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the lengths of the sides of a triangle are shown. 8.73, 12.4, and 10.075. what is the perimeter of the triangle

ElenaW [278]

Answer:

31.205

Step-by-step explanation:

The perimeter is the sum of the side lengths:

8.73 +12.4 +10.075 = 31.205

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3 years ago

- 7h + 2(-4h +5) > -4h +1 +10. Solve for h

navik [9.2K]

Hello.

-7h + 2(-4h + 5) > -4h + 1 + 10 ; solve for h

Our first step is to get rid of all the parenthesis. We can do this by simplifying everything out.

-7h - 8h + 10 > -4h + 11

Add like terms.

-15h + 10 > -4h + 11

Now, we must isolate our variables. We do this by moving all variables to one side and moving our other numbers to the other.

Subtract 10 from both sides. Then, add 4h to both sides.

-15h + 4h > 11 - 10

Simplify.

-h > 1

Divide both sides by -1.

However, keep in mind that when dividing with a negative, you must change the sign. Therefore, > turns into <

-h ÷ -1 < 1 ÷ -1

h < -1

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3 years ago

What is the volume of the rectangular prism?

Rufina [12.5K]

Answer:

$\large\boxed{Q1.\ 80\ cm^3}\\\boxed{Q2.\ 45\ in^3}\\\boxed{Q3.\ 48\ m^3}\\\boxed{Q4.\ A,\ D}\\\boxed{Q5.\ 96\ in^3}$

Step-by-step explanation:

$\text{The formula of a volume of a rectangular prism:}\\\\V=lwh\\\\l-length\\w-width\\h-height$

$\bold{Q1}\\\\l=10\ cm,\ w=4\ cm,\ h=2\ cm\\\\V=(10)(4)(2)=80\ cm^3\\\\\bold{Q2.}\\\\l=5\ in,\ w=3\ in,\ h=3\ in\\\\V=(5)(3)(3)=45\ in^3\\\\\bold{Q3.}\\\\l=4\ m,\ w=2\ m,\ h=6\ m\\\\V=(4)(2)(6)=48\ m^3\\\\\bold{Q4.}\\\\V=120\ ft^3\\\\\bold{A:(5)(4)(6)=120}\\B:\ (7)(7)(6)=294\\C:\ (3)(6)(4)=72\\\bold{D:\ (10)(3)(4)=120}\\\\\bold{Q5.}\\\\l=8\ in,\ w=4\ in,\ h=3\ in\\\\V=(8)(4)(3)=96\ in^3$