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3 years ago

Need help with number 2 please and thx

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

It is the second bubble because there can only be one x per y. For example, (1,3) and (1,4) isn't a function because the x which is 1 has too many y

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I need the help alot

GuDViN [60]

Answer:

{-5/4, 8}

Step-by-step explanation:

We are given (4u + 5)(8 - u) = 0. Solve for u by setting each of the factors (4u + 5) and (8 - u) equal to zero and solving each of the resulting equations:

4u + 5 = 0 leads to u = -5/4, and

8 - u = 0 leads to u = 8.

The solutions are {-5/4, 8}

8 0

3 years ago

Help pleaseeeeeeeeee

WARRIOR [948]

Answer:

first subtract 5 from each side

Step-by-step explanation:

7 0

3 years ago

What is the equation of the following line? Be sure to scroll down first to see

rusak2 [61]

Answer:I’m not sure I think it’s b

Step-by-step explanation:

3 0

3 years ago

Which ordered pair is a solution of the equation?<br> -x– 4y = -10

vodka [1.7K]

Answer:

D - Neither

Step-by-step explanation:

I did the problem :)

5 0

3 years ago

Read 2 more answers

someone pls help meeeee!!!!!!<br>

GuDViN [60]

Step-by-step explanation:

y = y

x - 2 = 2x - 3 - 3x²

3x² + x - 2x = - 3 + 2

3x² - x = - 1

a = 3, b = -1, c = 0

$\sf{x = \frac{-b \pm \sqrt{b^{2} - 4ac} }{2a} }$

$\sf{x = \frac{- (-1) \pm \sqrt{-1^{2} - 4 (0)} }{2(3)} }$

$\sf{x = \frac{ 1 \pm \sqrt{1 - 0} }{6} }$

$\sf{x = \frac{ 1 \pm \sqrt{1} }{6} }$

$\sf{x = \frac{ 1 + 1 }{6} }$

$\sf{x = \frac{ 2 }{6} }$

$\sf{x = \frac{ 1 }{3} }$

Substitution :

y = x - 2

y = ⅓ - 2

y = ⅓ - 6/3

y = - 5/3

y = - 1 ⅔

5 0

3 years ago