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3 years ago

Need help with number 2 please and thx

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

It is the second bubble because there can only be one x per y. For example, (1,3) and (1,4) isn't a function because the x which is 1 has too many y

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Which of the Following is the solution to 4|x+3| greater than equal to 8? Options are as followed: A.x less then equal to -5 or

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D x greater than equal to -5 and x greater y’all

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3 years ago

Sam reads 30 pages of a book in 40 minutes. Which statement identifies a person with the same reading rate as Sam?

zavuch27 [327]

Answer:

Choice 3

Step-by-step explanation:

The reading rate of Sam is 0.75 pages/minute.

i.e 30 pages/40 minutes

The reading rate of Bill is 0.5 pages/minute

The reading rate of Francine is 0.72 pages/minute

The reading rate of Leroy is 0.75 pages/minute which is the same as Sam's.

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3 years ago

An insurance policy sells for $800. Based on past data, an average of 1 in 50

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2 years ago

Simplify: -c - 8(4c - 5) - (-18c + 3)

d1i1m1o1n [39]

Answer:

-15c + 2

Step-by-step explanation:

you start by multiplying the coefficients of the parentheses to the numbers inside which gives you

- c - 32c + 5 + 18c - 3

then you simply just group together the like numbers. all "c" 's go together and everything without a "c" goes together

- 1c - 32c + 18c= -15c

5 - 3 = 2

the final answer simplified is

-15c + 2

6 0

3 years ago

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

$\frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)$

$\frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)$

Simplify the equation.

$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )$

Therefore, this is the 2nd derivative of the function f(x).

We can say that: $f''(x)=36x^2+4$

6 0

2 years ago

Read 2 more answers