Steph runs a vehicle body repair shop with one mechanic in Cleveland. Repair time for vehicles is exponentially distributed, wit
1 answer:
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Answer:
(x, y) = (5, -4)
Step-by-step explanation:
The second equation gives you an expression for x that can be substituted into the first equation.
(2y +13) -3y = 17 . . substitute for x in the first equation
-y = 4 . . . . . . . . . . . subtract 13 and simplify
y = -4
x = 2(-4) +13 = 5 . . . use the second equation to find the value of x
The solution is (x, y) = (5, -4).
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<em>Additional comment</em>
When faced with a system of linear equations, the first step is to look at them and observe where the variable terms are, and any relationships between coefficients. Several options are generally open to you for solving the equations. Methods generally taught first are ...
- substitution
- elimination
<em>Substitution</em> is handy when one of the variables or variable terms can be written (easily) in terms of the other variable. <em>Elimination</em> is handy when some simple multiple of one of the equations can be added to the other equation to cancel one of the variable terms (eliminate it).
Other available methods include matrix methods, Cramer's rule, and graphing. Working knowledge of all of these methods will help you identify the one that will be easiest to use in any given situation.
The availability of calculators able to use these methods greatly simplifies the task of finding a solution. It is simply a matter of entering the equations in the appropriate form.
One of my favorites is the graphing calculator, which only requires you type in the given equations and click on the solution point to find its coordinates.
