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lukranit [14]
3 years ago
5

2. What does a surface area/volume ratio of 6:1 mean for the cell’s ability to get the materials it needs that move across its s

urface?
Biology
2 answers:
igomit [66]3 years ago
6 0

Answer;

-A surface area/volume ratio of 6:1 means the cell's ability to get materials it needs that move across its surface is very efficient.

-Increased surface area to volume ratio makes diffusion and osmosis much more effective. Cellular concentrations of ions, nutrients, salts, etc can occur much more quickly and efficiently.

Explanation;

-The surface area to volume ratio of a cell is the relationship between two measurements.That is; the ratio of Surface area to volume. It shows the comparison between the size of the outside of a cell and the amount inside. Small or thin cells have a large surface area compared to the volume.

eduard3 years ago
4 0
It depends on the unit of the ratio 6:1. If it is in <span>c<span>m<span>−1</span></span></span><span>, then it means that it is similar to a cell of size 1 cm^3,
 which is normally too big to get materials from the surface
hope it helps</span>
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The immunoglobulin light chain does not have a D segment. In humans, there are two different possible light chain proteins, term
wlad13 [49]

Answer:

295  

Explanation:

Antibodies (also known as immunoglobulins) are immune system-related proteins that circulate in the bloodstream in order to recognize pathogenic harmful substances (antigens) and neutralize them. An antibody consists of two immunoglobulin heavy chains and two immunoglobulin light chains. There are two types of immunoglobulin light chains: 1-the kappa (κ) light chain, which is encoded by the immunoglobulin κ locus; and 2-the lambda (λ) light chain, which is encoded by the immunoglobulin λ locus. The immunoglobulin light chain is a multidomain protein composed of two domains: 1- the N-terminal variable (V) domain and 2-the C-terminal constant (C) domain. V(D)J recombination is a type of somatic rearrangement process by which T and B cells can assemble different gene segments, which are referred to as variable (V), diversity (D) and joining (J) gene segments. In the question above the number of possible genomic recombination events between immunoglobulin gene segments can be calculated as >> (5 x 35) + (4 x 30) = 295.

4 0
2 years ago
I need help with this (#20)
tester [92]

Answer:

a Anaphase I

b Metaphase I

c Telophase I

d Anaphase II

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f Telophase II

Explanation:

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Explanation:

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