What number is understood to be the coefficient (number in front of) of x2 a) 0 B) 1

The radius of a circle is 2 m. Find the circumference to the nearest tenth.

Y_Kistochka [10]

Answer:

25.13 or 25.1

Step-by-step explanation:

2 x pi/3.14x4

6 0

2 years ago

Find the equation of a line that contains the points (−3,−1) and (−4,−7). Write the equation in slope-intercept form

ikadub [295]

Answer:

y = -8x -25

Step-by-step explanation:

The 2-point form of the equation of a line is useful when you are given 2 points.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (7 -(-1))/(-4 -(-3))(x -(-3)) +(-1)

y = 8/-1(x +3) -1

y = -8x -25

7 0

2 years ago

I need HELP PLZZZZ THIS IS DUE AT 7:00

valkas [14]

Answer:

27.5

Step-by-step explanation:

1.5(5)+20=27.5

:) hope its right :)

7 0

2 years ago

Read 2 more answers

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for h:

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for h.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

2 years ago

Evaluate the expression:–|20| + |5|

Svetradugi [14.3K]

-|20| + |5| = -15

Steps:
Apply absolute rule: |a| = a, a >/ 0
|20| = 20
= -20+5
Apply absolute rule: |a| = a, a >/ 0
|5| = 5
= -20+5
Refine
= -15

Hope this helps you! (:
-Hamilton1757

3 0

3 years ago