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N76 [4]
3 years ago
8

That is wrong it is 3 1/2

Mathematics
1 answer:
butalik [34]3 years ago
7 0

Answer:

or 3.5

Step-by-step explanation:

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Maria finds a local gym that advertises 67 training sessions for $2052. Find the cost of 153 training sessions.
Ann [662]

Answer:

Cost\ of\ 153\ training\ sessions\ =\$4685.9\approx\$4686

Step-by-step explanation:

Cost\ of\ 67\ training\ sessions\ =\$2052\\\\Cost\ of\ 1\ training\ sessions\ =\frac{Total\ cost}{Total\ training\ sessions}\\\\Cost\ of\ 1\ training\ sessions\ =\frac{2052}{67}\\\\Cost\ of\ 153\ training\ sessions\ =153\times cost\ of\ 1\ training\ sessions\ \\\\Cost\ of\ 153\ training\ sessions\ =153\times\frac{2052}{67}=4685.9\\\\Cost\ of\ 153\ training\ sessions\ \$4685.9\approx4686

7 0
3 years ago
One of the tables shows a proportional relationship.
IRINA_888 [86]
The 2nd option is the answer :)!
4 0
3 years ago
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Let f(x) = 8x3 + 16x2 − 15 and g(x) = 2x + 1. Find f of x over g of x.
andrey2020 [161]

Answer:

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3 0
2 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
Eighteen subtracted from half a number is 38.<br> Find the number.
Andrews [41]

Answer:

x=112

Step-by-step explanation:

x/2-18=38

first add +18

x/2=56

now multiply by 2

x=112


6 0
3 years ago
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