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3 years ago

Which type of validity applies to research results based on subjective qualities?

2 answers:

7 0

The answer is concurrent validity.

This kind of validity is based on comparing the results with a measure that has been validated previously.

It is used in more subjective qualities given that they cannot be measured with instruments but it is more an appreciation that depends on the subject that performs the test.

Mumz [18]3 years ago

7 0

the answer is face validity

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-3(2r-4) > 2(5-3r) Whats the inequality?

VLD [36.1K]

-3 (2r - 4) > 2 (5 - 3r)
-6r + 12 > 10 - 6r
12 > 10

There is no solution

4 0

3 years ago

Read 2 more answers

define a variable write an equation and solve the problem. the length of a rectangle is twice the width. an equation that models

liberstina [14]

6w=36
w=6

width=6
length=12

7 0

3 years ago

A building is 964 feet tall. Two people are standing on the ground directly west of the building. The

Lina20 [59]

Answer:

The distance from both of them = 1463.925 ft

Step-by-step explanation:

The building is 964 ft tall . 2 people are standing on the ground directly west of the building. The first person looks up at an angle of 62° to the top of the building while the second person did same at an angle of 26°. The distance between them can be computed below.

The illustration forms a right angle triangle . Using the SOHCAHTOA principle let us find the distance of the second person from the building

tan 26° = opposite/adjacent

tan 26° = 964/adjacent

adjacent tan 26° = 964

adjacent = 964/tan 26°

adjacent = 964/0.48773258856

adjacent = 1976.49290328 ft

The distance from the second person to the building = 1976.493 ft

Distance of the first person to the building

tan 62° = opposite/adjacent

tan 62° = 964/adjacent

adjacent tan 62° = 964

adjacent = 964/tan 62°

adjacent = 964/1.88072646535

adjacent = 512.567892122

distance from the first person to the building = 512.568 ft

The distance from both of them = 1976.493 ft - 512.568 ft = 1463.925 ft

5 0

3 years ago

Help please please I need the answer Quick!

Ber [7]

Answer:

Step-by-step explanation:

Need to account for getting to and from the trail as well

7 0

3 years ago

The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min

Deffense [45]

Answer:

f'(t) is negative

The unit is degC/min

At 35 minutes after the coffee was put on the counter, its temperature is 68 and will decrease by about 0.75 in the next 30 seconds.

Step-by-step explanation:

From the question we are told we are told that

The equation for the temperature of a cup of coffee place on a counter is

$H= f(t)$

Here t is the time in minutes the coffee was put on the counter

Generally f(t)' is the derivative of f(t) at it represents the change of the temperature of the cup of coffee with respect to time

Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence f(t)' is negative

Generally the unit of the temperature is in degrees Celsius while that of time is in minutes

So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e degC/min)

From the question we are told that

$|f(35)'| = 1.5$

i.e the rate of change of temperature after 35 minutes is 1.5

and

$|f(35)| = 68$

i.e the temperature of the cup of coffee after 35 minutes is 67 degC

Now after another t= 30 seconds = $\frac{30}{60}= 0.5 \ minutes$ the rate of change of the temperature of the cup of coffee is

$R = |f(35)'| * t$

=> $R = 1.5 * 0.5$

=> $R = 0.75$

At 35 minutes after the coffee was put on the counter, its temperature is 68 and will decrease by about 0.75 in the next 30 seconds.

5 0

3 years ago