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Lemur [1.5K]
3 years ago
14

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Seven h

undred and eighty feet of fencing is used. Find the dimensions of the playground that maximize the total enclosed area. What is the maximum​ area?
Mathematics
1 answer:
Arisa [49]3 years ago
8 0

Answer:

Step-by-step explanation:

Suppose the dimensions of the playground are x and y.

The total amount of the fence used is given and it is 780 ft. In terms of x and y this would be 3x+2y=780 (we add 3x because we want it to be cut in the middle). Therefore,  y= 780/2-3/2x. Now, the total area (A )to be fenced is

A=x*y= x*(390-3/2x)=-3/2 x^2+390x

Calculating the derivative of A and setting it equals to 0 to find the maximum

A'= -3x+390=0

This yields x=130.

Therefore y=780/2-3/2*130=195

Thus, the maximum area is 130*195=25,350ft^2

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Paul's budget for food is 30% of the budget he has for rent.
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Paul's rent budget is <u>$750</u>, given that his food budget of $225, is 30 percent of his rent budget.

<h3> What are fractions?</h3>

Fractions are representation of quantities as a part of a certain quantity.

Written as <u>a/b</u>, read as <u>a by b</u>, and functions as <u>a divided by b</u>, represents a fraction showing a parts of b equal parts.

a is called the numerator, and b is called the denominator.

<h3>What are percentages?</h3>

Percentages are modified fractions where the whole quantity is represented by 100.

To convert a fraction into percentages we multiply it by 100, while to convert percentages to fraction divided by 100.

<h3>How to solve the question?</h3>

In the question, we are given that Paul's budget for food is 30% of the budget he has for rent.

We are asked if his budget for food is $225, what is his budget for rent.

We assume Paul's budget for rent to be $x.

We know that Paul's food's budget is 30 percent of his rent.

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Thus, Paul's rent budget is <u>$750</u>, given that his food budget of $225, is 30 percent of his rent budget.

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