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Lemur [1.5K]
3 years ago
14

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Seven h

undred and eighty feet of fencing is used. Find the dimensions of the playground that maximize the total enclosed area. What is the maximum​ area?
Mathematics
1 answer:
Arisa [49]3 years ago
8 0

Answer:

Step-by-step explanation:

Suppose the dimensions of the playground are x and y.

The total amount of the fence used is given and it is 780 ft. In terms of x and y this would be 3x+2y=780 (we add 3x because we want it to be cut in the middle). Therefore,  y= 780/2-3/2x. Now, the total area (A )to be fenced is

A=x*y= x*(390-3/2x)=-3/2 x^2+390x

Calculating the derivative of A and setting it equals to 0 to find the maximum

A'= -3x+390=0

This yields x=130.

Therefore y=780/2-3/2*130=195

Thus, the maximum area is 130*195=25,350ft^2

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27.27 %

Step-by-step explanation:

% = part/whole * 100%

(12/44)*100 ≈ 27. 27%

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Molly bought a large basket of 60 apples.
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Answer:

approximately 14

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first find out how many sets of 60 there are

200/60=3.3

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but you can't have 2/3 of a rotten apple

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2 years ago
Pleaseee help I need fast and right
Alinara [238K]

Answer: e. x≠2             f. x≥-1/2

Step-by-step explanation:

Domain is basically the x value of a function.

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Question e.

g(x)=5/(2-x)

First, keep in mind, the denominator of a fraction can not be zero or else it will be undefined.

Since x is in the denominator: 2-x≠0

2-x≠0

<h2>    x≠2 Yes, this is the domain</h2>

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h(x)=√(2x+1)

For a standard square root, the value inside can't b negative

So 2x+1≥0

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3 years ago
Sienna used the scale drawing above to create a pool that is 14 ft wide x 22 ft long. She then decided to make pool with a final
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A scale factor allows a shape to be changes into another shape by changing  the linear dimensions to the multiples of the initial dimension and a constant

The expression that finds the change in scale factor for the longer pool with a final length of 33 ft. Sierra is building is the option;

  • \dfrac{2 \, ft.}{3 \, ft.}

Reason:

Known parameters are;

Dimensions of the pool created = 14 ft. wide × 22 ft. long

Final length of the pool = 33 ft.

Let <em>x</em> represent the length of the drawing using the initial scale factor, we have;

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The scale factor of the drawing following a final length of 33 ft. is therefore;

  • New \ scale \ factor = \dfrac{33 \, ft.}{x \, in.}

The change in scale factor is given as follows;

Change \ in \ scale \ factor = \dfrac{Initial \, scale \, factor}{Final \, scale \, factor}

Therefore;

  • Change \ in \ scale \ factor = \frac{\left( \dfrac{22 \, ft.}{x \, in.} \right)}{\left( \dfrac{33 \, ft.}{x \, in.} \right)} = \dfrac{2 \, ft.}{3 \, ft.}

Learn more here;

brainly.com/question/17637896

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36/11

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