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Serhud [2]
3 years ago
13

Matt decides the length of his table will be 15 in. He calculates that the area of the table is 30 in. squared. Determine if Mat

t’s calculation is correct
Mathematics
1 answer:
Allushta [10]3 years ago
8 0

Answer:No Matt's calculation is not correct.

Step-by-step explanation:

We have to multiply by the number of the area.If it is 4 inches we multiply by 4

15 x 4 =60

A=4 inches squared

A=LxW (length x width )

so you can say that:

Matt is incorrect because He skipped  the step of multiplying 2 by 2 in the formula which is where we get 4 from.

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What is the mean of this data set? If necessary, round your answer to the
Marizza181 [45]

Answer:

40.1

Step-by-step explanation:

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3 years ago
HELP!! REAL answers only please.
Alika [10]

Answer:

33

Step-by-step explanation:

So the angle of 40 is a vertical angle with the one opposite of it, meaning that the triangle on the left would have two values of 40 and 41, to find the value of the 3rd angle of the left triangle, you can subtract 40 and 41 from 180 which is the total number of degrees in a triangle to get 99, then you can find the degrees of the triangle on the right's bottom angle by subtracting 99 from 180, meaning the bottom left angle would be 81, then you can do the same to find the other angle by subtracting 114 from 180 to get 66. Lastly you can add 81 and 66 to get 147, then subtracting 147 from 180 you would get x=33

3 0
3 years ago
Find the distance from the point (1,4) to the line y = 1/3x - 3
Troyanec [42]

Answer:

Step-by-step explanation:

If I'm not mistaken, and I very well could be, this is a calculus problem(?). In order to find the distance without calculus you'd need a point on the given line to use to find the distance in the distance formula. But you don't have a point on the given line, so we can find the shortest distance between the point (1, 4) and the given line using the derivative of the polynomial formed when using the distance formula.

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} and we have the x and y for x2 (or x1...it doesn't matter which you choose to fill in):

d=\sqrt{(1-x)^2+(4-y)^2}

but what we find is that we have too many unknowns here, namely, the distance, the x coordinate, and the y coordinate. So we can replace the y coordinate with what y is equal to in terms of the linear equation:

d=\sqrt{(1-x)^2+(4-\frac{1}{3}x-3)^2 } and simplify:

d=\sqrt{(1-x)^2+(7-\frac{1}{3}x)^2 }

. No we'll expand each binomial by squaring:

d=\sqrt{(1-2x+x^2)+(49-\frac{14}{3}x+\frac{1}{9}x^2)  }

.  Combining like terms gives us

d=\sqrt{\frac{10}{9}x^2-\frac{20}{3}x+50  }

The distance between the point (1, 4) and the given line will be at a minimum when the polynomial above is at a minimum. We find the value of x for which the polynomial is at a minimum by finding its derivative, setting the derivative equal to 0, and then solving for x. The derivative of the polynomial is

\frac{20}{9}x-\frac{20}{3}

Setting equal to 0 and getting rid of the denominators gives us

20x - 60 = 0

Solving for x gives us

20x = 60 and x = 3.

That's the value of x that gives us the shortest distance between (1, 4) and the line y = 1/3x - 3. Sub into the distance formula that x value to find the distance:

d=\sqrt{(\frac{10}{9})(3)^2-(\frac{20}{3})(3)+50   }

which simplifies down, finally, to

x ≈ 6.325 units

8 0
3 years ago
Find ordered pairs: choose two of the answers below
Anarel [89]

Answer:

b -3,3 c 6,9 hope this helps

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3 years ago
I need question 3 only
dsp73

Answer:

  • table: 14, 16, 18
  • equation: P = 2n +12

Step-by-step explanation:

Perimeter values will be ...

rectangles . . . perimeter

  1 . . . 14

  2 . . . 16

  3 . . . 18

__

The perimeter of a figure is twice the sum of the length and width. Here, the length is a constant 6. The width is n, the number of rectangles. So, the perimeter is ...

  P = 2(6 +n) = 12 +2n

Your equation is ...

  P = 2n +12 . . . . . . . . perimeter P of figure with n rectangles.

_____

<em>Additional comment</em>

You may be expected to write the equation using y and x for the perimeter and the number of rectangles. That would be ...

  y = 2x +12 . . . . . . . . . perimeter y of figure with x rectangles

4 0
3 years ago
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