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adell [148]
3 years ago
10

There are 160 deer on Manitow Island. The population of deer is growing by approximately 20% per year. Write an equation using d

ecimal form that can be used to find the amount of years,y, it will take for there to be approximately 450 deer on the island.
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0
I believe the equation would be
160+0.2y

Because 160 deer and you round the 20% into a decimal point.
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IRISSAK [1]
Three thousand five hundred eight
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3 years ago
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Solve the equation with quadratic formula<br> y^2+3y-10=0
neonofarm [45]

Answer:

y = 2 and y = -5

Step-by-step explanation:

Because the coefficient is not greater than 1, you can simply solve the problem without the quadratic formula.

By using the "x" method, you must figure out what multiplies to give you -10, and adds to give you 3

So, you find your values as 5 and -2. You then set these values equal to zero in terms of Y. As so---- (y+5)=0 and (y-2)=0

Then, you solve out to get your answer! Y is equal to -5 and 2

6 0
3 years ago
An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
3 years ago
. An object dropped from a height of 200 meters has a height, h(t), in meters after t seconds have lapsed, such that h(t) = 200
Veronika [31]

Answer:

t(h)= (h-200)/-4.9

The time to reach a height of 50 meters is 30.6 seconds

Step-by-step explanation:

To express t as a function of height (h) we must transform the equation below:

h=200-4.9t

h-200=-4.9t

(h-200)/-4.9=t

t(h)= (h-200)/-4.9

To find the time to reach a height of 50 meters, we must replace this value on the new equation:

t(h)=50-200/-4.9

t(h)= 30.612

The time to reach a height of 50 meters is 30.6 seconds

8 0
4 years ago
Best answer get Brainliest. 50 points.
Oliga [24]
<span>The equation would be 5x + 0.10y = 35, and since y equals 100, the 0.10y = 10. Then you get your equation which would be 5x + 10 = 35. and you can use subtraction property of equality and subtract 10 from both sides which gives you 25. So x would equal 5. In this case x represents number of dogs walked. Hope this helps! :D</span>
3 0
3 years ago
Read 2 more answers
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