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3 years ago

12r+5+3r-5 Need you help

Mathematics

1 answer:

iren [92.7K]3 years ago

7 0

Answer:

15r

Step-by-step explanation:

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Three quarters of the boats in the marina are white, 4/7 of the remaining boats are blue, adn the rest are red. If there are 9 r

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3 years ago

5 decades 4 years 3 months -2 decades 5 years 6 months =

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28.75 years

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the answer to:

velikii [3]

Weird way to write it but alright! (Sideways)

19pq^-2 x 5pq^6 = ?

These problems are pretty much single operations between each of the variables / constants.

So it's like this:

(19*5)(p*p)(q^-2*q^6) = ?

19*5 is 95.

For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.

p*p is p^2

For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:

-2 + 6 = 4
(The two is negative, because the power is negative 2)

So, q^4.

Our final answer is all of the combined.... like a so:

95p^2q^4

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3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

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3 years ago

Write the equation of a line in slope-intercept form with a slope of -1/3 and a y intercept of 4

Sergeu [11.5K]

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