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Oksi-84 [34.3K]
3 years ago
13

What are the factors of 9a-3

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

9, -3

Step-by-step explanation:

You might be interested in
Please help me!!!!!!
cestrela7 [59]

Answer:

I am sorry but this is too difficult

Step-by-step explanation:

I recommend asking a teacher for help not to be rude

6 0
3 years ago
In a chess tournament, each player plays every other player exactly once. If it is known that 105 games were played, how many pl
diamong [38]

Answer:

15 players played in the chess tournament.

Step-by-step explanation:

When there are 15 players, the first player plays 14 games and step aside.

remaining 14 player

next player plays 13 games. steps aside

remaining 13 players

next player plays 12 games. steps aside

remaining 12 players

next player plays 11 games. steps aside

remaining 11 players

.

.

.

.

Last player plays 1 game and steps aside

remaining 1 player who will not play against himself.

∴ Sum of all games played

= 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105 games played

3 0
3 years ago
Hello everyone good morning how is everyone doing to day
Zepler [3.9K]
I’m tired I’ve so much homework to complete and a long day of school :(
5 0
3 years ago
Read 2 more answers
1.How many combinations are possible from the letters HOLIDAY if the letters are taken?
Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

Exercise 1, item a:

One letter from a set of 7, hence:

C_{7,1} = \frac{7!}{1!6!} = 7

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

C_{7,2} = \frac{7!}{2!5!} = 21

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

C_{7,7} = \frac{7!}{0!7!} = 1

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0
2 years ago
4) What is the present value of $4000 received at the
Bingel [31]

Answer:

$11040

Step-by-step explanation:

first of all the question says that $4000 were earned in a year and asks for what the new vale would be after the next 3 years with a discount rate of 8%.

If 1 year=$4000,then 3 years=$12000

100%-8%=92% (this happens because there is still a remaining amount that still has a cost to it),so 12000*92%=$11040

8 0
3 years ago
Read 2 more answers
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