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3 years ago

A rectangle is dilated by a scale factor of 4.

1 answer:

7 0

A) The new dimensions would be 32cm by 12cm.
B) This is an enlargement.

To find the new dimensions, multiply the original dimensions by the scale factor. 8*4=32 and 3*4=12.

This is an enlargement because the copy is larger than the original.

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You have 24 apples and you get rid of 12. How many do you have left?

24-12=x

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3 years ago

What mistake did she make while solving the problem?

umka2103 [35]

Answer:

Ms, Erickson added 6x^3 plus -3x^2 and these terms have different exponents.l

Step-by-step explanation:

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3 years ago

Which equation represents a line which is parallel to the line 2x+y=-6?

joja [24]

The answer is: [C]: " y = -2x - 1 " .
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5 0

3 years ago

A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte

AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

$\angle SPR$ =Angle subtended by the statue to where you are standing.

$\angle x=\angle RPQ$ = which is unknown.

Let us begin solving now. The first step is to find the angle $\angle x$ which can be found by using the following trigonometric ratio in $\Delta PQR$ :

$tan(x)=\frac{RQ}{PQ} =\frac{21}{57}$

Which gives $\angle x$ to be:

$\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}$

Now, we know that $\angle x$ and $\angle SPR$ can be added to give us the complete angle $\angle SPQ$ in the right triangle $\Delta SPQ$ .

We can again use the tan trigonometric ratio in $\Delta SPQ$ to solve for the height of the statue, h.

This can be done as:

$tan(\angle SPQ)=\frac{SQ}{PQ}$

$tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}$

$tan(27.32^0)=\frac{h+21}{57}$

$\therefore h+21=57tan(27.32^0)$

$h\approx8.45 ft$

Thus, the height of the statue is approximately, 8.45 feet.

3 0

3 years ago

If x and y in the equations

Brums [2.3K]

We can let
a = 1/(x-1)
b = 1/(y+2)
and rewrite the equations as
2a - b = 10
a + 3b = -9
Using the first to write an expression for b, we get
b = 2a - 10
Substituting this into the second equation gives
a + 3(2a -10) = -9
7a -30 = -9 . . . . . . . . simplify
7a = 21 . . . . . . . . . . .add 30
a = 3
b = 2·3 - 10 = -4

Now, we can find x and y.
   3 = 1/(x -1)
   x - 1 = 1/3
   x = 1 1/3 = 4/3

  -4 = 1/(y +2)
  y +2 = -1/4
  y = -2 1/4 = -9/4

Then the desired sum is
  x + y = 4/3 -9/4 = (16 -27)/12
x + y = -11/12

The appropriate choice is ..
c. -11/12

5 0

3 years ago