1/3=2/6
5/6x2/6= 10/36
10/36 simplified is 5/18
If 0.3 = 1 then 0.9 = 3 because 0.3+0.3+0.3=the 3.
Answer:
Step-by-step explanation:
a. Profit, p, earned from selling x hats when hat will be sold for $12 each:
p = 12x
b. To recover the cost of making the 200 hats which is $1500, profit, p >= cost:
p = 12x >= 1500
x >= 1500/12 = 12.5
So the minimum number of hats that must be sold = 13
c. New hat price = $15 so p = 15x
p = 15x >= 1500
x >= 1500/15 = 10
So the new minimum = 10 which is 3 fewer.
At the start you will start with $7 and $7.60 there is a simple way and a more complex process. The simple way is using the formula of y=mx+b so y=.8x+7 and the other way is just too add .8 to 7 and .7 to 7.6 and keep doing that till you get the answer. The answer is 7, seven topping have to be added to make them the same price.
If you mean "factor over the rational numbers", then this cannot be factored.
Here's why:
The given expression is in the form ax^2+bx+c. We have
a = 3
b = 19
c = 15
Computing the discriminant gives us
d = b^2 - 4ac
d = 19^2 - 4*3*15
d = 181
Note how this discriminant d value is not a perfect square
This directly leads to the original expression not factorable
We can say that the quadratic is prime
If you were to use the quadratic formula, then you should find that the equation 3x^2+19x+15 = 0 leads to two different roots such that each root is not a rational number. This is another path to show that the original quadratic cannot be factored over the rational numbers.
