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meriva
2 years ago
10

What is the answer to this please help

Mathematics
2 answers:
mash [69]2 years ago
7 0

Answer:

2\sqrt{42} + 7\sqrt{2} -6- \sqrt{21}

Step-by-step explanation:

(\sqrt{14} - \sqrt{3})(\sqrt{12} + \sqrt{7})

root 12 can be changed to 2 root 3

then multiply

then simply

and you should get ur answer

Elis [28]2 years ago
4 0

Answer:

use calculater please it will not take long

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What is the are of a circle that measures 12 ft in diameter?<br>​
Alexus [3.1K]

Answer:

113.04

Step-by-step explanation:

the equation for the area of a circle is pie times radius squared

5 0
2 years ago
Given f(x)=2x-8, find f(3)
IgorLugansk [536]
F(3)=2*3-8=-2. 
Hope that helps. 
6 0
2 years ago
The expression 8x2 − 144x 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represent
Rzqust [24]

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Given expression 8x² − 144x + 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represents the number of years since 1998.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Given expression is 8x² − 144x + 864

Let y = 8x² − 144x + 864

also,  y - 864 = 8x² - 144x

by Extracting common factor 8 on the right side

y - 864 = 8(x² - 18x)

Add (18/2)² on both sides, we get

y - 864 + 8(18/2)² = 8 (x² - 18x + 81²)

y - 864 + 648 = 8 (x² - 8x + 9)

on simplification

y - 216 = 8 (x - 9)²

y = 8(x - 9)² + 216

therefore, y = 8 (x - 9)² + 216

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Learn more about a quadratic equation here:

brainly.com/question/2263981

8 0
1 year ago
The per capita growth rate of many species varies temporally for a variety of reasons, including seasonality and habitat destruc
Veronika [31]

Answer:

n(t)=n_0e^{(1-e^{-t }-t)}

Step-by-step explanation:

If n(t) represents the population size at time t, where n is measured in individuals and t is measured in years.

\frac{dn}{dt}=n(e^{-t }-1), n(0)=n_o

\frac{dn}{n}=(e^{-t }-1)dt

Taking the integral of both sides

\int\frac{dn}{n}=\int(e^{-t }-1)dt\\\int\frac{dn}{n}= \int e^{-t }dt-\int1dt

ln |n| = -e^{-t }-t+C

Where C is integration constant

Taking the exponential of both sides

n=e^{(-e^{-t }-t+C)}

n=e^{(-e^{-t }-t)}e^C\\n=Ke^{(-e^{-t }-t)} whee the exponential of a constant is a constant K.

When t=0, n(0)=n_o

n_0=Ke^{-1

Therefore:

n=n_0e^{1}e^{(-e^{-t }-t)}

n(t)=n_0e^{(1-e^{-t }-t)}

7 0
3 years ago
The scale of map is 1cm : 70km. What is the actual distance between towns that are 5cm apart on the map
Illusion [34]

Answer: 350km

Step-by-step explanation:

Since we are informed that the scale of map is 1cm : 70km. Therefore, the actual distance between towns that are 5cm apart on the map will be:

= 5 × 70km

= 350km

Therefore, the answer is 350km

3 0
2 years ago
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