(x-2) + (x-1) + x + (x+1) + (x-2) + (x+3) = 447
6x + 3 = 447
6x = 447 - 3
6x = 444
x = 444/6
x = 74
The answer to how many batches is 9, hope this helped.
What we know so far:
Side 1 = 55m
Side 2 = 65m
Angle 1 = 40°
Angle 2 = 30°
What we are looking for:
Toby's Angle = ?
The distance x = ?
We need to look for Toby's angle so that we can solve for the distance x by assuming that the whole figure is a SAS (Side Angle Side) triangle.
Solving for Toby's Angle:
We know for a fact that the sum of all the angles of a triangle is 180°; therefore,
180° - (Side 1 + Side 2) = Toby's Angle
Toby's Angle = 180° - (40° + 30°)
Toby's Angle = 110°
Since we already have Toby's angle, we can now solve for the distance x by using the law of cosines r² = p²+ q²<span>− 2pq cos R where r is x, p is Side1, q is Side2, and R is Toby's Angle.
</span>
x² = Side1² + Side2² - 2[(Side1)(Side2)] cos(Toby's Angle)
x² = 55² + 65² - 2[(55)(65)] cos(110°)
x² = 3025 + 4225 -7150[cos(110°)]
x² = 7250 - 2445.44
x = √4804.56
x = 69.31m
∴The distance, x, between two landmarks is 69.31m
a^2 + b^2 = c^2
Let c = hypotenuse = 2x
One of the legs = x. Let a or b = x.
I will let a = x. We can then say that b = 3.
3^2 + x^2 = (2x)^2
9 + x^2 = 4x^2
9 = 4x^2 - x^2
9 = 2x^2
9/2 = x^2
sqrt{9/2} = sqrt{x^2}
3/sqrt{2} = x
Rational denominator.
[3•sqrt{2}]/2 = x = a
Side 3 is given to be 3 feet. So, b = 3.
Hypotenuse = 2x
Hypotenuse = 2([3•sqrt{2}]/2)
Hypotenuse = 3•sqrt{2}
Understand?
The three sides are 3, [3•sqrt{2}]/2 and
3•sqrt{2}.
Answer:
The missing length is 2x+5
Step-by-step explanation:
Given equation of volume of cuboid is V= 
Figure show that
Length of cuboid is ?
Width of cuboid is (x+4)
Height of cuboid is (x+2)
The volume of cuboid is given by
V=Length x Width x Height
Let Length be (bx+a)
The volume of cuboid will be
![V=(bx+a)[x^{2}+4x+2x+8 ]](https://tex.z-dn.net/?f=V%3D%28bx%2Ba%29%5Bx%5E%7B2%7D%2B4x%2B2x%2B8%20%5D)
![V=bx[x^{2}+6x+8]+a[x^{2}+6x+8]](https://tex.z-dn.net/?f=V%3Dbx%5Bx%5E%7B2%7D%2B6x%2B8%5D%2Ba%5Bx%5E%7B2%7D%2B6x%2B8%5D)
![V=[bx^{3}+6bx^{2}+8bx]+[ax^{2}+6ax+8a]](https://tex.z-dn.net/?f=V%3D%5Bbx%5E%7B3%7D%2B6bx%5E%7B2%7D%2B8bx%5D%2B%5Bax%5E%7B2%7D%2B6ax%2B8a%5D)
![V=[bx^{3}+(6b+a)x^{2}+(8b+6a)x+8a]](https://tex.z-dn.net/?f=V%3D%5Bbx%5E%7B3%7D%2B%286b%2Ba%29x%5E%7B2%7D%2B%288b%2B6a%29x%2B8a%5D)
On comparing coefficient with given equation of volume
We get,
b=2 and 8a=40
Therefore, the value of a is 5 and b is 2
Thus, The missing length is bx+a=2x+5
