Answer:
CD = 6.385 units
Step-by-step explanation:
Given triangle ABC with right angle at C.
And AB = AD + 6 .
Now, consider the triangle ABC.
⇒ cos(∠BAC) = (cosФ = adj/hyp)
cos(20) = .
0.9397 =
(since AB = AD + 6 and AC = AD + CD)
⇒ 0.9397 AD + 5.6382 = AD + CD
⇒ CD = 0.0603 AD + 5.6382. →→→→→ (1)
⇒ sin(∠BAC) = (sinФ = opp/hyp)
sin(20) = .
⇒ BC = AB sin(20) . →→→→→(2)
Now, consider the triangle BCD,
sin(∠BDC) =
⇒ sin(80) =
CD =
From (2), CD = .
⇒ CD = AB (0.3473)
⇒ CD = (AD + 6) (0.3473)
⇒ CD = 0.3473 AD + 2.0838 →→→→→→(3)
Now, (1) →→ CD = 0.0603 AD + 5.6382
(3) →→ CD = 0.3473 AD + 2.0838
⇒ 0.0603 AD + 5.6382 = 0.3473 AD + 2.0838
0.287 AD = 3.5544.
⇒ AD = 12.3847
⇒ From (1), CD = 0.0603(12.3847) + 5.6382
⇒ CD = 6.385 units
That's correct but whats your question?
Answer:
-7
Step-by-step explanation:
The two lines intersect at the point (6,10), so this point belongs to both lines. This means that if we use the value of x = 6 in the lines, we will find y = 10
So we can use this point to find the values of b and m:
y = mx + 4
10 = 6m + 4
6m = 6
m = 1
y = 3x + b
10 = 3*6 + b
b = 10 - 18 = -8
So the value of b + m is -8 + 1 = -7
24x? i haven’t done these in a while so lmk if i’m wrong